In this problem, it is essential to use the order of operations, or PEMDAS (parentheses, exponents, multiplication, division, addition, subtraction). First, you solve 7-3=4. Then, you multiply 7 times 4, which is 28. Lastly, you add 28 to 156 which is 184. So your answer is B.
Answer:
(A) h(x) = 1/4x -2
Step-by-step explanation:
Given: f(x)=4x+8
Rewrite with y: y=4x+8
Switch x and y: x=4y+8
Solve for y: x-8=4y
(x-8)/4=y
1/4x-2=y
y=1/4x-2
This means that h(x) = 1/4x -2 is the correct answer
Answer:
identity property of addition-
a+0=a
identity property of multiplication-
a*1=a
Step-by-step explanation:
i cant give u an exact answer as u didnt give Micheals answers so i just gave some examples about what addition and multiplication identity property should look like. Identity property's concept is to keep the same identity. Basically, "a" shouldnt change. In addition, to keep a the same all u hv to do is add 0 as anything plus 0 is the same. for multiplication, just multiply by 1. Hope this helps!!
Part A. You have the correct first and second derivative.
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Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.
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Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out
To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0.
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well.
