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LUCKY_DIMON [66]
3 years ago
11

PLSS HELPP 25 POINTS AND BRAINLIEST

Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
4 0

Answer:

I believe it would be 3 meters...

dont kill me if im wrong!

Step-by-step explanation:

RideAnS [48]3 years ago
3 0

Answer:

\Large \boxed{\sf 150 \ m^2}

Step-by-step explanation:

Surface area of this shape = area of 2 triangles + area of 3 rectangles

(12 \times 5 \times 0.5 \times 2 )+(13 \times 3+12 \times 3+5 \times 3)= 150

Height of the triangular base is 12 m.

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Urgent!! <br> Answer like this. “3rd graph goes to the 4th item drop” please or however you want :)
Setler79 [48]

Answer:

graph 1 = greater than 1

graph 2 = 0

graph 3 = 0

graph 4 = less than 0

graph 5 - between 0 & 1

Sorry if anything is wrong!!

5 0
3 years ago
I NEED LOTS OF HELP IF U ANSWER THIS CORRECTLY I WILL GIVE YOU BRAINLYIST PLEASE PLEASE PLEASE ANSWER THIS
muminat
Which question???????????
4 0
2 years ago
The temperature, T, of a given mass of gas varies inversely with its Volume,V. The temperature of 98 cm ³ of a certain gas is 28
Naily [24]

Answer:

T₂ = 421.4 K

Step-by-step explanation:

The temperature, T, of a given mass of gas varies inversely with its Volume,V.

T\propto \dfrac{1}{V}\\\\V_1T_1=V_2T_2

We have,

V₁ = 98 cm³, T₁ = 28° C = (28+273) K = 301 K

V₂ = 70 cm₃

We need to find the new temperature of the gas. Using the above relation to find T₂.

T_2=\dfrac{V_1T_1}{V_2}\\\\T_2=\dfrac{98\times 301}{70}\\\\T_2=421.4\ K

Hence, the required temperature of the gas is 421.4 K.

4 0
2 years ago
Can someone please help me out with this?
pshichka [43]

Answer:

B. segment AG is congruent to segment OL

Step-by-step explanation:

5 0
3 years ago
The table shows the total distance that Myra runs over different time periods.
Oliga [24]

Answer:

its d

Step-by-step explanation:

4 0
3 years ago
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