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3 years ago

Complete the equations so that the solution of the system of equations is (−1, −4). y= ?X−11 6x− ? Y=10

Mathematics

1 answer:

eimsori [14]3 years ago

8 0

Answer:

y = –7x – 11

6x – 4y = 10

Step-by-step explanation:

From the question given above, we obtained:

x = –1

y = –4

y = ?x – 11 ....... (1)

6x – ?y = 10b......... (2)

Let the two unknown be a and b. Thus the above equation becomes:

y = ax – 11 ......... (3)

6x – by = 10 .......(4)

Next, we shall determine the value of 'a' and 'b'. This can be obtained as follow:

For a:

y = ax – 11

x = –1

y = –4

–4 = a(–1) – 11

–4 = –a – 11

Collect like terms

–4 + 11 = –a

7 = –a

Multiply through by –1

a = –7

For b:

6x – by = 10

x = –1

y = –4

6(–1) – b(–4) = 10

–6 + 4b = 10

Collect like terms

4b = 10 + 6

4b = 16

Divide both side by 4

b = 16 / 4

b = 4

Finally, we shall substitute the value of a and be into equation 3 and 4 respectively.

y = ax – 11

a = –7

y = –7x – 11

6x – by = 10

b = 4

6x – 4y = 10

Therefore, the complete equation are:

y = –7x – 11

6x – 4y = 10

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3 years ago

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The number of minutes advertisement should use is found.

x ≅ 12 mins

Step-by-step explanation:

(MISSING PART OF THE QUESTION: AVERAGE WAITING TIME = 2.5 MINUTES)

For such problems, we can use probability density function, in which probability is found out by taking integral of a function across an interval.

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Solve the equation for x

$\int\limits^{\infty}_x {0.4e^{-0.4t}} \, dt =0.01\\\\\frac{0.4e^{-0.4t}}{-0.4}=0.01\\\\-e^{-0.4t} |^\infty_x =0.01\\\\e^{-0.4x}=0.01$

Take natural log on both sides

$ln (e^{-0.4x})=ln(0.01)\\-0.4x=ln(0.01)\\-0.4x=-4.61\\x= 11.53$

<h3>Results</h3>

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3 years ago

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(* I'm actually not totally sure that continuity is necessary for the AROC to exist; I've asked this question before without getting a particularly satisfying answer.)

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which would mean all the terms in-between would need to be doubled as well to get

$\displaystyle\int_a^b f(x)\,\mathrm dx\approx\frac{b-a}n\left(y_0+2y_1+2y_2+\cdots+2y_{n-1}+y_n\right)$

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