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frez [133]
3 years ago
6

Suppose that a number written as a decimal has an infinite number of non-repeating digits after the decimal point. What is this

number called?
Oirational
natural
unnatural
rational
Hell yall
Mathematics
1 answer:
emmasim [6.3K]3 years ago
8 0

Answer:

Irrational

Step-by-step explanation:

The number is called an irrational number.

These numbers have some distinct properties. The number of numbers after the decimal point is infinite. What this means is that it does not terminate. It keeps on repeating.

Also, these numbers cannot be represented as a ratio of two integers i.e two whole numbers. This is because they keep on going without termination.

Lastly is that these numbers do not repeat after decimal. What I mean by this is that they do not keep repeating a particular number after the decimal point. For example in cases like 2.33333; these are infinite too, but they can be represented by the ratio of two whole numbers and in such cases, they are not irrational in their own respect

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djyliett [7]

First, you are going to distribute the 3 into the (6x+2x) and the 8 into the (5x+6). After that, the parenthesis should be gone. Then, move all the x values to one side, and the constants to the other. Then, solve as you normally would.

6 0
2 years ago
Describe the error made when converting the equation to vertex form.
ale4655 [162]

Answer:

adding 36

Step-by-step explanation:

should be:

y-27=x²-12x

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+12 +12

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3 0
2 years ago
Use quadratic formula solve .7x^2 - 28x - 7​
beks73 [17]

Answer:

x = 2 + sqrt(5) or x = 2 - sqrt(5)

Step-by-step explanation using the quadratic formula:

Solve for x over the real numbers:

7 (x^2 - 4 x - 1) = 0

Divide both sides by 7:

x^2 - 4 x - 1 = 0

Add 1 to both sides:

x^2 - 4 x = 1

Add 4 to both sides:

x^2 - 4 x + 4 = 5

Write the left hand side as a square:

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Take the square root of both sides:

x - 2 = sqrt(5) or x - 2 = -sqrt(5)

Add 2 to both sides:

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Add 2 to both sides:

Answer:  x = 2 + sqrt(5) or x = 2 - sqrt(5)

6 0
3 years ago
3 / m + 4 - 4 / m = 6 (i) Show that this equation can be written as 6m^2 + 25m+16= 0
Evgen [1.6K]

Answer:

Proved Below

Step-by-step explanation:

\sf \frac{3}{m+4} - \frac{4}{m} = 6\\LCM = m(m+4)\\Multiplying \ both \ sides \ by\ m(m+4)\\3m - 4(m+4) = 6m(m+4)\\3m-4m-16 = 6m^2+24m\\-m-16 = 6m^2+24m\\Adding\ m\ to\ both\ sides\\-16 = 6m^2+24m+m\\-16 = 6m^2+25m\\Adding \ 16 \ to \ both \ sides\\0 = 6m^2+25m+16\\OR\\6m^2+25m+16 = 0

Hence, Proved that \sf \frac{3}{m+4} - \frac{4}{m} = 6 is equivalent to \sf 6m^2+25m+16 = 0.

6 0
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