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ikadub [295]
3 years ago
9

12x - 3x + 11 3 4x - (17 - 9x)

Mathematics
2 answers:
KengaRu [80]3 years ago
8 0

sorry it won't let me show step by step but your answer is 150x-17

Irina-Kira [14]3 years ago
7 0

Answer:

I’m not really sure what’s the problem but I searched it,, hope that helps

Step-by-step explanation:

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Kelly earns a 7% commission on the total amount of her sales. This year, she had $210,000 in sales.
Minchanka [31]
I will find comission

7% of 210000

percent means parts out of 100
7%=7/100
7/100 times 210000=1470000/100=14700

comission is $147000
3 0
3 years ago
Read 2 more answers
Find the slope of the line that passes through (6, 3) and (3, 2).
hjlf

Answer:

1/3

Step-by-step explanation:

Slope m = (y2-y1)/(x2-x1)

m = (2 - 3)/(3 - 6) = (-1)/(-3) = 1/3

8 0
3 years ago
What is the value of 5 in 102,587​
andrew-mc [135]
5 is in the hundredth place
6 0
3 years ago
How many people will there be if I have 58 friends and each of them bring five friends, but 6 of my friends are couples? So, how
Zanzabum

Answer:

276 individuals at the party.

Step-by-step explanation:

If 6 of your friends are couples then we would count them as 1 each and it would be 3 friends. Therefore we subtract 3 from your 58 friends.

58 - 3 = 55 friends

Each of them brings 5 friends so we multiply your number of friends by 5.

55 * 5 = 275 friends

Finally, we add you because you are included

275 + 1 = 276

There will be a total of 276 individuals at the party.

4 0
3 years ago
Calculate the number of kilograms of mercury required to fill a pool that is 20.0 m x 50.0 m x 10.0 m. The density of mercury is
malfutka [58]

Answer:

m=135000000 Kg

Step-by-step explanation:

To find the number of kilograms of mercury we need to find how to relate density, mass and, volume. For this we shall recall the density formula:

\rho=\frac{m}{V}

where \rho is the density, m is the mass and, V is the volume.

We have the density and want to compute the mass so now we want to know the volume of the pool.

The volume of a rectangular pool is given by the fomula:

V= (length)(heigh)(width).

So for our pool

V= (20)(50)(10).

V= 10000m^{3}.

Our density is in g/mL, so the last thing we need to do before computing the mass is to express the density in Kg/m^{3} (this is because we want our mass in Kg and, we have our volume in m^{3}).

For the density conversion we have to remember that

1000mL = 1L

1L=0.001m^{3}

1000g=1Kg

so

\rho=13.5\frac{g}{mL}*\frac{1000mL}{1L}*\frac{1L}{0.001m^{3}}*\frac{1Kg}{1000g}   =13500\frac{Kg}{m^{3}}.

With this we can finally compute mass:

\rho=\frac{m}{V}

m=\rho*V

m=(13500*10000) Kg

m=135000000 Kg.

4 0
3 years ago
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