Answer:
D y-8 +2 ≤ -2+2
Step-by-step explanation:
y-8 ≤ -2
Add 2 to each side
y-8 +2 ≤ -2+2
The box does not let me write in it....
Answer : The correct option is 
Step-by-step explanation :
According to the BODMAS rule, when the expression contains brackets open ((), {}, []) we have to first simplify the bracket followed by of (powers and roots etc.) and then we have to solve the division, multiplication, addition and subtraction from left to right order (respectively).
The given expression is:
![[\frac{(2a^{-3}b^4)^2}{(3a^5b)^{-2}}]^{-1}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%282a%5E%7B-3%7Db%5E4%29%5E2%7D%7B%283a%5E5b%29%5E%7B-2%7D%7D%5D%5E%7B-1%7D)
![=[\frac{(3a^5b)^{-2}}{(2a^{-3}b^4)^2}]^{1}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B%283a%5E5b%29%5E%7B-2%7D%7D%7B%282a%5E%7B-3%7Db%5E4%29%5E2%7D%5D%5E%7B1%7D)
![=[\frac{1}{(3a^5b)^{2}}\times \frac{1}{(2a^{-3}b^4)^2}]](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1%7D%7B%283a%5E5b%29%5E%7B2%7D%7D%5Ctimes%20%5Cfrac%7B1%7D%7B%282a%5E%7B-3%7Db%5E4%29%5E2%7D%5D)
![=[\frac{1}{9a^{10}b^2}\times \frac{1}{4a^{-6}b^8}]](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1%7D%7B9a%5E%7B10%7Db%5E2%7D%5Ctimes%20%5Cfrac%7B1%7D%7B4a%5E%7B-6%7Db%5E8%7D%5D)
![=[\frac{1}{9a^{10}b^2}\times \frac{a^6}{4b^8}]](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1%7D%7B9a%5E%7B10%7Db%5E2%7D%5Ctimes%20%5Cfrac%7Ba%5E6%7D%7B4b%5E8%7D%5D)

Thus, the given expression is equivalent to 
Answer:
(1/7)(-9n + 7)
Step-by-step explanation:
1/7-3(3/7n-2/7) can be factored: factor out 1/7.
We get: (1/7)[1 - 3(3n - 2)], or
(1/7)[1 - 9n + 6], or
(1/7)(-9n + 7)