Answer:
sorry I don't know the answer I just wrote something for this im a beginner
Given the expression 
Take a logarithm 
from both side of the given expression:
From the property 
you have that
Then
Answer: correct choice is C
The correct answer is y= 0.513(1.833)^x
Explain
We will use the equation on this form
Y=ab^x
Let’s us plug in the coordinates of first point
(X, y) , ( 9, 120)
We will have
Y=ab^x
120= ab^9
Our equation for a will be
Ab^9 = 120
ab ^9 / b^9 = 120/ b^9
a = 120/ b^9
So will have
Y= 120/ b^9 • b^x
Then we will plug in coordinates for the second point
( x,y) = ( 10, 220)
We will have
Y= 120/b^9 • b^x
220 = 120/b^9 • b^10-9
220= 120b
Divide both side by 120
B= 11/6
B= 1.833333 = 1.833
Let’s plug in the value b=11/6 to our equation for a
A= 120/b^9
A= 120/ 11/6^9
A= 120/11^9/6^9
A=120 • 6^9 / 11^9
= 0.51285 which equal to 0.513
So therefore the answer is
Y= 0.513(1.833)^x
I hope this help you
:D
What was ur bday last year and then add one day onto it. So say last year it was Tuesday then this year it would be Wednesday
Answer:
a. 21 327 hot dogs/run
b. 70 runs/yr
c. 4 da/run
Step-by-step explanation:
Data:
Production rate (p) = 5000/da
Usage rate (u) = 260/da
Setup cost (S) = $66
Annual carrying cost (H) = $0.45/hot dog
Production days (d) = 294 da
Calculations:
a. Optimal run size
(i) Annual demand (D) = pd = (5000 hot dogs/1 day) × (294 days/1 yr)
= 1 470 000 hot dogs/yr
(ii) Economic run size
= 21 327 hot dogs/run
b. Number of runs per year
Runs = D/Q₀ = (1 470 000 hot dogs/1yr) × (1 run/21 327 hotdogs)
= 70 runs/yr
c. Length of a run
Length = Q₀/p = (21 327 hot dogs/1 run) × (1 da/5000 hot dogs)
= 4 da/run
