volume = 4/3 x PI x r^3
r = 10/2 =5
V = 4/3 x 3.14 x 5^3 = 523.333
523.3 cubic inches
In your question that ask to calculate the area of one of the tiles if a semicircular archway in the front of the garden is using 8 congruent granite tiles and the area of one of the tiles is 2.9ft ^2. I hope you are satisfied with my answer and feel free to ask for more.
Answer:
225 square centimeters
Step-by-step explanation:
The answer is $45 it wasn’t that hard
Answer:
35.25
Step-by-step explanation:
Give the data set:
23 37 49 34 35 41 40 26 32 22 38 42
We are expected to calculate the midquartile of the given data set.
22 23 26 32 34 35 37 38 40 41 42 49
First step is to find the lower quartile which comprises of
22 23 26 32 34 35
Here the Q1 is (26+32)/2 = 58/2= 29
Second step to find the upper quartile which comprises of
37 38 40 41 42 49
Here the Q3 is (40+41) /2 = 81/2 = 41.5
Then to find the midquartile which is (Q1+Q3) /2 where Q1 is 29 and Q3 is 41.5
= (29+41.5)/2
= (70.5) /2 = 35.25
