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koban [17]
3 years ago
8

The formula for the area of a triangle is A=1/2bh, where b is the base of the triangle and h is the height of the triangle. The

area of the triangular sail of a sailboat is 126ft^2. The base is 12 ft. Find the height of the sail.
(Show steps please)
Mathematics
1 answer:
eimsori [14]3 years ago
6 0

Answer:

H=21ft

Step-by-step explanation:

Height=2•Area/Base

Area=126ft^2

Base=12ft.

H=2•126/12=21ft

H=21ft

Hope this helps :)

You might be interested in
20 points Return to questionItem 4Item 4 20 points Police records in the town of Saratoga show that 13 percent of the drivers st
Sladkaya [172]

Answer:

a) 0.1423

b) 0.2977

c) 0.56

Step-by-step explanation:

For each driver stopped for speeding, there are only two possible outcomes. Either they have invalid licenses, or they do not. The probability of a driver having an invalid license is independent from other drivers. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

13 percent of the drivers stopped for speeding have invalid licenses.

This means that p = 0.13

14 drivers are stopped

This means that n = 14

(a) None will have an invalid license.

This is P(X = 0)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{14,0}.(0.13)^{0}.(0.87)^{14} = 0.1423

(b) Exactly one will have an invalid license.

This is P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{14,1}.(0.13)^{1}.(0.87)^{13} = 0.2977

(c) At least 2 will have invalid licenses.

Either less than 2 have invalid licenses, or at least 2 does. The sum of the probabilities of these events is decimal 1. Mathematically, this is

P(X < 2) + P(X \geq 2) = 1

We want P(X \geq 2)

So

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1) = 0.1423 + 0.2977 = 0.44

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.44 = 0.56

8 0
3 years ago
Please help thanks so much.
Alik [6]
You can see if they are similar by looking at the sides.

If each of the sides have the same proportion then they are similar.

24/3 = 8
32/4 = 8
112/14 = 8

Yes they are similar and their ratio is 1:8

Hope this helps :)
3 0
3 years ago
Read 2 more answers
1. The product of two consecutive integers <br> is 20. Find the values of these integers.
gulaghasi [49]
First find the factors of 20
1 & 20
2 & 10
4 & 5
-1 & -20
-2 & -10
-4 & -5

Now find the pairs that have a difference of 1

-4 & -5
4 & 5
4 0
3 years ago
The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d
jek_recluse [69]

Answer:

50%

Step-by-step explanation:

68-95-99.7 rule

68% of all values lie within the 1 standard deviation from mean (\mu-\sigma,\mu+\sigma)

95% of all values lie within the 1 standard deviation from mean  (\mu-1\sigma,\mu+1\sigma)

99.7% of all values lie within the 1 standard deviation from mean  (\mu-3\sigma,\mu+3\sigma)

The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4.

\mu = 55\\\sigma = 4

68% of all values lie within the 1 standard deviation from mean (\mu-\sigma,\mu+\sigma) = (55-4,55+4)= (51,59)

95% of all values lie within the 2 standard deviation from mean  (\mu-1\sigma,\mu+1\sigma)= (55-2(4),55+2(4))= (47,63)

99.7% of all values lie within the 3 standard deviation from mean  (\mu-3\sigma,\mu+3\sigma)= (55-3(4),55+3(4))= (43,67)

Refer the attached figure

P(43<x<55)=2.5%+13.5%+34%=50%

Hence The approximate percentage of light bulb replacement requests numbering between 43 and 55 is 50%

4 0
3 years ago
What is the value of x^2 divided by y^4 when x=8 and y=2
7nadin3 [17]

Answer:

4

Step-by-step explanation:

64/16=4

7 0
3 years ago
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