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Elden [556K]
2 years ago
8

NEED HELP PLEASE!

Mathematics
1 answer:
USPshnik [31]2 years ago
5 0

Answer:

(x + (3+5i))^2 = x^2 + 6x + (10x+30)i - 16

Step-by-step explanation:

Complex numbers identity:

The complex numbers identity is:

i^2 = -1

Square of the sum:

(x + y)^2 = x^2 + 2xy + y^2

In this question:

(x + (3+5i))^2

x^2 + 2x(3+5i) + (3+5i)^2

x^2 + 6x + 10xi + 9 + 30i + 25i^2

x^2 + 6x + 9 + (10x+30)i - 25

x^2 + 6x + (10x+30)i - 16

So

(x + (3+5i))^2 = x^2 + 6x + (10x+30)i - 16

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