Question

NEED HELP PLEASE!

Answer 1

Answer:

$(x + (3+5i))^2 = x^2 + 6x + (10x+30)i - 16$

Step-by-step explanation:

Complex numbers identity:

The complex numbers identity is:

$i^2 = -1$

Square of the sum:

$(x + y)^2 = x^2 + 2xy + y^2$

In this question:

$(x + (3+5i))^2$

$x^2 + 2x(3+5i) + (3+5i)^2$

$x^2 + 6x + 10xi + 9 + 30i + 25i^2$

$x^2 + 6x + 9 + (10x+30)i - 25$

$x^2 + 6x + (10x+30)i - 16$

So

$(x + (3+5i))^2 = x^2 + 6x + (10x+30)i - 16$