Answer:
3000 notebooks
Step-by-step explanation:
75000 sheets
each sheet has 8 pages
each notebook has 200 pages so,
75000x8=600000
600000/200=3000
1/3--------------------------
Answer:
![\sqrt[7]{x^{4}}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bx%5E%7B4%7D%7D)

![(\sqrt[7]{x})^{4}](https://tex.z-dn.net/?f=%28%5Csqrt%5B7%5D%7Bx%7D%29%5E%7B4%7D)
Step-by-step explanation:
we have

Remember the properties
![\sqrt[n]{a^{m}}=a^{\frac{m}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%7D%3Da%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D)

so
<u><em>Verify each case</em></u>
Part 1) we have
![\sqrt[4]{x^{7}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E%7B7%7D%7D)
we know that
![\sqrt[4]{x^{7}}=x^{\frac{7}{4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E%7B7%7D%7D%3Dx%5E%7B%5Cfrac%7B7%7D%7B4%7D%7D)
Compare with the given expression

Part 2) we have
![\sqrt[7]{x^{4}}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bx%5E%7B4%7D%7D)
we know that
![\sqrt[7]{x^{4}}=x^{\frac{4}{7}}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bx%5E%7B4%7D%7D%3Dx%5E%7B%5Cfrac%7B4%7D%7B7%7D%7D)
Compare with the given expression

therefore
Is equivalent to the given expression
Part 3) we have

we know that

Compare with the given expression

therefore
Is equivalent to the given expression
Part 4) we have
we know that

Compare with the given expression

Part 5) we have
![(\sqrt[4]{x})^{7}](https://tex.z-dn.net/?f=%28%5Csqrt%5B4%5D%7Bx%7D%29%5E%7B7%7D)
we know that
![(\sqrt[4]{x})^{7}=(x^{\frac{1}{4}})^{7}=x^{\frac{7}{4}}](https://tex.z-dn.net/?f=%28%5Csqrt%5B4%5D%7Bx%7D%29%5E%7B7%7D%3D%28x%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%29%5E%7B7%7D%3Dx%5E%7B%5Cfrac%7B7%7D%7B4%7D%7D)
Compare with the given expression

Part 6) we have
![(\sqrt[7]{x})^{4}](https://tex.z-dn.net/?f=%28%5Csqrt%5B7%5D%7Bx%7D%29%5E%7B4%7D)
we know that
![(\sqrt[7]{x})^{4}=(x^{\frac{1}{7}})^{4}=x^{\frac{4}{7}}](https://tex.z-dn.net/?f=%28%5Csqrt%5B7%5D%7Bx%7D%29%5E%7B4%7D%3D%28x%5E%7B%5Cfrac%7B1%7D%7B7%7D%7D%29%5E%7B4%7D%3Dx%5E%7B%5Cfrac%7B4%7D%7B7%7D%7D)
Compare with the given expression

therefore
Is equivalent to the given expression
79. Set up an equation to solve this problem. Suppose she needs at least a score of x points. Her current total scores is 89+65+68+88=310. Her total score will be 310+2x (since final exams counts as two tests). The average score is total points divided by number of tests, and it has be bigger or equal to 78, so (310+2x)/6>=78. We solve it and get x=79. She has to score at least 79 on her final exam in order to jhave an overall average of 78.
Answer:
(1) Multiplication by 25
Step-by-step explanation: