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Phoenix [80]
2 years ago
13

Select ALL the expressions that are equivalent to -4(8x-3)

Mathematics
1 answer:
Vinvika [58]2 years ago
8 0

Answer:

dddddStep-by-step explanation:

You might be interested in
(10x5)+(30+20)x10-100-1=
Flauer [41]

Answer:

899 would be your answer

Step-by-step explanation:

10x5=50

50+30=80

80+20=100

100x10=1000

1000-100=900

900-1=899

Hope this helps you!

5 0
3 years ago
Read 2 more answers
Tereka and Emma each deposit money in savings accounts. The amount of money, in dollars, in Tereka’s account after x years is mo
Over [174]

Given:

Amount of money in Tereka’s account : T(x)=472(1.04)^x

Amount of money in Emma’s account : E(x)=485(1.09)^x

To find:

The difference between initial amounts Tereka and Emma deposit.

Solution:

Substitute x=0 in the given functions, to get the initial amount of money they deposit.

T(0)=472(1.04)^0

T(0)=472(1)

T(0)=472

So, the initial amount Tereka deposit is $472.

E(0)=485(1.09)^0

E(0)=485(1)

E(0)=485

So, the initial amount Emma deposit is $485.

Difference between the initial amounts Tereka and Emma deposit is

485-472=13

Therefore, the difference between initial amounts Tereka and Emma deposit is $13. Emma deposit $13 more than Tereka.

6 0
3 years ago
Help me please! I'd really appreciate it
Svetllana [295]
The ratio of the sides are the same. So 6/24=x/56. This leads to x being 14.
4 0
3 years ago
Two quantities vary inversely. If the value of the first is 15 when the value of the second is 18, find the value of the second
vovikov84 [41]

Answer:

The value of second quantity is 27

Step-by-step explanation:

Inverse variation can be represented by the equation xy=k or y = \frac{k}{x} i.e,

y varies inversely as x , if there is some nonzero constant k such that, xy =k or y = \frac{k}{x} where  x≠0 and y≠0.

Given: Two quantities vary inversely.

Let x be the first quantity and y be the second quantity if they  vary inversely.

then, by definition of inverse variation;

y = \frac{k}{x}            .....[1]

Substitute the value of x=15 and y=18 to solve for k;

18= \frac{k}{15}

Multiply both sides by 15 we have;

15\times 18=15 \times \frac{k}{15}

Simplify:

k=270

now, find  the second quantity y using same method when x=10.

then;

after substituting the value of x=10 and k=270 in [1] ;

y = \frac{270}{10}

Simplify:

y= 27

Therefore, the second quantity value i.e,y = 27



7 0
3 years ago
Read 2 more answers
At a candy store, Erika bought 3 kilograms of cinnamon red hots and 1 kilogram of gummy bears for $21.00. Meanwhile, Irene bough
ch4aika [34]
31. At the candy store: => Ericka bought 3 kilograms of Cinnamon red hots and 1 kilograms of gummy bears for 21.00 dollars. => Irene bought 3 kilograms of cinnamon red hots and 3 kilograms of gummy bears for 39.00 dollars. Question: Find the costs of each kilograms. Notice that the cinnamon red hot that they both are the same, the only difference is the gummy bears, which added 2kilos for Irene. Now, let’s subtract => 39 – 21 = 18 dollars – this is the costs of 2 kilos of gummy bear => 18 / 2 = 9 dollars, thus the price of each kilos of gummy bear is 9 dollars, Now, let’s solve for the cinnamon => 21 – 9 = 12 dollars, to be divided with 3 kilos => 12 / 3 = 4 dollars – the price of cinnamon red hot per kilo.
5 0
3 years ago
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