Answer:
n=-4 x=-7
Step-by-step explanation:
No
Both share the same x-values which means it isn’t a function
Hope this helps ;)
Answer:
Step-by-step explanation:
A ' = (-2, -3)
B ' = (0, -3)
C ' = (-1, 1)
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Explanation:
To apply an x axis reflection, we simply change the sign of the y coordinate from positive to negative, or vice versa. The x coordinate stays as is.
Algebraically, the reflection rule used can be written as
Applying this rule to the three given points will mean....
Point A = (-2, 3) becomes A ' = (-2, -3)
Point B = (0, 3) becomes B ' = (0, -3)
Point C = (-1, -1) becomes C ' = (-1, 1)
The diagram is provided below.
Side note: Any points on the x axis will stay where they are. That isn't the case here, but its for any future problem where it may come up. This only applies to x axis reflections.
3)

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6)

*************************************************************************************
7)
