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alexandr1967 [171]

2 years ago

9

A scale drawing of a patio is shown at right. The scale is 3 inches : 5.2 feet. What are the length and width of the patio? Find

the patio’s area. (ASAP please)

2 answers:

weeeeeb [17]2 years ago

8 0

Answer:quizyouo

Step-by-step explanation:

ANTONII [103]2 years ago

5 0

Answer:

The length is 5.2 and the width is 3 and the area is 15.6

Step-by-step explanation:

To get the area just multiply width by length

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What multiplication problem is equivalent to 3 3/8 divide by 3/8

Anni [7]

The expression $3\frac{3}{8}\div \frac{3}{8}$ can be written in multiplication problem as: $3\frac{3}{8}\times \frac{8}{3}$ or $\frac{27}{8}\times \frac{8}{3}$

Step-by-step explanation:

We need to find What multiplication problem is equivalent to $3\frac{3}{8}\div \frac{3}{8}$

We are given: $3\frac{3}{8}\div \frac{3}{8}$

Writing it in multiplication problem.

When division sign is changed to multiplication sign, the fraction is reciprocated.

$3\frac{3}{8}\div \frac{3}{8}$

Converting division into multiplication

$3\frac{3}{8}\times \frac{8}{3}$

or we can write as:

$\frac{27}{8}\times \frac{8}{3}$

So, the expression $3\frac{3}{8}\div \frac{3}{8}$ can be written in multiplication problem as: $3\frac{3}{8}\times \frac{8}{3}$ or $\frac{27}{8}\times \frac{8}{3}$

Keywords: Solving Fractions

Learn more about Solving Fractions at:

#learnwithBrainly

4 0

2 years ago

What is 5x5x3x5x3x2 simplified using exponents

8090 [49]

Answer: 5 to the 3rd times 3 to the second times 2

Step-by-step explanation:

8 0

3 years ago

1. an alloy contains zinc and copper in the ratio of 7:9 find weight of copper of it had 31.5 kgs of zinc.

m_a_m_a [10]

Answer:

Step-by-step explanation:

Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.

If the weight of an alloy = x kgs

Then weight of copper = $\frac{9}{7+9}\times (x)$

= $\frac{9}{16}\times (x)$

And the weight of zinc = $\frac{7}{7+9}\times (x)$

= $\frac{7}{16}\times (x)$

If the weight of zinc = 31.5 kg

31.5 = $\frac{7}{16}\times (x)$

x = $\frac{16\times 31.5}{7}$

x = 72 kgs

Therefore, weight of copper = $\frac{9}{16}\times (72)$

= 40.5 kgs

2). i). 2 : 3 = $\frac{2}{3}$

4 : 5 = $\frac{4}{5}$

Now we will equalize the denominators of each fraction to compare the ratios.

$\frac{2}{3}\times \frac{5}{5}$ = $\frac{10}{15}$

$\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}$

Since, $\frac{12}{15}>\frac{10}{15}$

Therefore, 4 : 5 > 2 : 3

ii). 11 : 19 = $\frac{11}{19}$

19 : 21 = $\frac{19}{21}$

By equalizing denominators of the given fractions,

$\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}$

And $\frac{19}{21}\times \frac{19}{19}=\frac{361}{399}$

Since, $\frac{361}{399}>\frac{231}{399}$

Therefore, 19 : 21 > 11 : 19

iii). $\frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}$

$=\frac{3}{2}$

$\frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}$

= $\frac{4}{3}$

Now we equalize the denominators of the fractions,

$\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}$

And $\frac{4}{3}\times \frac{2}{2}=\frac{8}{6}$

Since $\frac{9}{6}>\frac{8}{6}$

Therefore, $\frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4}$ will be the answer.

IV). $1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}$

$=\frac{6}{5}\times \frac{3}{4}$

$=\frac{18}{20}$

$=\frac{9}{10}$

Similarly, $\frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}$

$=\frac{4}{15}$

By equalizing the denominators,

$\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}$

Similarly, $\frac{4}{15}\times \frac{20}{20}=\frac{80}{300}$

Since $\frac{270}{300}>\frac{80}{300}$

Therefore, $1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}$

V). If a : b = 6 : 5

$\frac{a}{b}=\frac{6}{5}$

$=\frac{6}{5}\times \frac{2}{2}$

$=\frac{12}{10}$

And b : c = 10 : 9

$\frac{b}{c}=\frac{10}{9}$

Since a : b = 12 : 10

And b : c = 10 : 9

Since b = 10 is common in both the ratios,

Therefore, combined form of the ratios will be,

a : b : c = 12 : 10 : 9

7 0

2 years ago

Find the first four terms for the arithmetic sequence given a1 = 6 and d = 5

DENIUS [597]

Answer:

6, 11, 16, 21

Step-by-step explanation:

To obtain the first 4 terms add the common difference 5 to the previous term, that is

a₁ = 6

a₂ = a₁ + 5 = 6 + 5 = 11

a₃ = a₂ + 5 = 11 + 5 = 16

a₄ = a₃ + 5 = 16 + 5 = 21

7 0

2 years ago

Witch 2 numbers are 4 units away from zero on a number line

Liula [17]

Answer:

it depends which way youre going, but 4 and -4 work.

Step-by-step explanation:

6 0

2 years ago