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Phantasy [73]
3 years ago
11

Solve and simplify 3. (y^2-7y-5)-(-3y^2+3y-4)

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
7 0

(y^2-7y-5)-(-3y^2+3y-4)=y^2-7y-5-(-3y^2)-3y-(-4)\\\\=y^2-7y-5+3y^2-3y+4

<em>combine like terms</em>

=(y^2+3y^2)+(-7y-3y)+(-5+4)=\boxed{4y^2-10y-1}

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Write a polynomial function that meets the stated conditions.The zeros are −2 and 1.
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Answer:

A polynomial function that meet those conditions is x² + x - 2 = 0

Step-by-step explanation:

Hi there!

To solve this problem, let´s start writting a generic polynomial function in factored form. Since the function has two zeros, the factored form will have 2 terms:

(x+a)(x+b) = 0

For this equation to be 0, (x+a) or (x+b) have to be zero:

Then:

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In the same way:

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In our case:

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