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Phantasy [73]
3 years ago
11

Solve and simplify 3. (y^2-7y-5)-(-3y^2+3y-4)

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
7 0

(y^2-7y-5)-(-3y^2+3y-4)=y^2-7y-5-(-3y^2)-3y-(-4)\\\\=y^2-7y-5+3y^2-3y+4

<em>combine like terms</em>

=(y^2+3y^2)+(-7y-3y)+(-5+4)=\boxed{4y^2-10y-1}

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(3.8 x 10 ^ -6) x (2.37 x 10 ^ -3)<br><br> Enter the answer in science notification
Black_prince [1.1K]

Multiply the coefficients and the powers of 10 with each other:

(3.8 \times 10^{-6}) \times (2.37 \times 10^{-3}) = (3.8\times2.37) \times (10^{-6} \times10^{-3})

The numeric part simply yields

3.8\times2.37 = 9.006

As for the powers of 10, you have to add the exponents, using the rule

a^b \times a^c = a^{b+c}

So, we have

10^{-6} \times10^{-3} = 10^{-6-3} = 10^{-9}

So, the final answer is

9.006\times 10^{-9}

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3 years ago
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Third expression

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=> (3 x 3) x (3 x 3 x 3)

=> 9 x 27, the product is also equals to 243.

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3 years ago
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Answer:

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