Answer:
<h2>x=-2 or x=8</h2>
Step-by-step explanation:
Isolate by the x from one side of the equation.
|x-3|=5
x-3=-5 and x-3=5
1. x-3=-5
Add 3 from both sides.
x-3+3=-5+3
Solve.
-5+3=(-2)
x=-2
2. x-3=5
Add 3 from both sides.
x-3+3=5+3
Solve.
5+3=8
x=8
Therefore, the correct answer is x=-2 or x=8.
<u>Answer-</u>
<em>Area of the triangle is </em><em>10 sq.units</em>
<u>Solution-</u>
We know that,
![\text{Area of the triangle}=\dfrac{1}{2}[{x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20the%20triangle%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5B%7Bx_1%28y_2-y_3%29%2Bx_2%28y_3-y_1%29%2Bx_3%28y_1-y_2%29%5D)
Taking,
(x₁, y₁) = (3, 3)
(x₂, y₂) = (3, -1)
(x₃, y₃) = (-2, -5)
Then putting these in the formula,
![\text{Area of the triangle}=\dfrac{1}{2}[3(-1+5)+3(-5-3)-2(3+1)]](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20the%20triangle%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5B3%28-1%2B5%29%2B3%28-5-3%29-2%283%2B1%29%5D)
![=\dfrac{1}{2}[3(4)+3(-8)-2(4)]](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1%7D%7B2%7D%5B3%284%29%2B3%28-8%29-2%284%29%5D)
![=\dfrac{1}{2}[12-24-8]](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1%7D%7B2%7D%5B12-24-8%5D)
![=\dfrac{1}{2}[-20]](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1%7D%7B2%7D%5B-20%5D)
As area can not be negative, ignoring negative sign,
Answer:
A or 53 squared
Step-by-step explanation:
Answer:
21
Step-by-step explanation:
I used a triangle area calculator.
Hope I helped!
Answer: You can't. Read explanation.
Step-by-step explanation:
You can't subtract an expression from an equation. If you said something like subtract 8b-ab+7a from 3a-9ab+b that would work, but not here.
Let's just assume You mean it as 8b-ab-7a, then (3a-9ab+b)-(8b-ab-7a) = -8ab + 10a - 7b.
Hope that helped,
-sirswagger21
