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Naddik [55]
3 years ago
8

Carl's Comic Books bought a comic book from a wholesaler for $2.50. He marked the book up

Mathematics
1 answer:
Ray Of Light [21]3 years ago
3 0

Answer:

150 should be the answer

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What is the vertex of the absolute value function below?
erastovalidia [21]

Answer:

(-3,2)

Step-by-step explanation:

Go where the two coordinates match, you'll see that it's (-3,2).

I see that that's Edge2021, I know how that feels. :/

Hope this helped! :)

3 0
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DO Y'ALL KNOW THE ANSWER?
marissa [1.9K]

Answer:

A

Step-by-step explanation:

just a guess

7 0
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20 POINT QUESTION!!<br><br> Complete the equation of the linear function.<br><br><br> y = <br> x +
Viefleur [7K]
A=(0,1); B=( \frac{1}{2}, 0) \\ &#10;y=ax+b&#10; &#10;\left \{ {{1=0a+b} \atop {0= \frac{1}{2}+b }} \right.  \\ &#10; \left \{ {{1=b} \atop { \frac{1}{2}a=-b}} \right.  \\ &#10; \left \{ {{b=1} \atop {a=-2}} \right. &#10;&#10;y=-2x+1
8 0
3 years ago
A probability experiment is conducted in which the sample space of the experiment is upper s equals startset 4 comma 5 comma 6 c
olchik [2.2K]
The correct question statement is:

A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in E^{c}. Find P(E^{c}).

Solution:

Part 1:

E^{c} means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.

So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:

E^{c}=S-E \\  \\ &#10;E^{c}=(4,5,6,7,8,9,10,11,12,13,14,15)-(7,8,9,10,11,12,13,14,15) \\  \\ &#10;E^{c}=(4,5,6)

Thus the set compliment of E will contain the elements {4,5,6}.So

E^{c} = {4,5,6}

Part 2)

P(E^{c}) means probability that if we select any number from the Sample Space S, it will belong the set E compliment.

P(E^{c}) = (Number of Elements in E^{c})/Number of elements in S

Number of elements in set S = n(S) = 12
Number of elements in set E^{c} = n(E^{c})=3

So, 

P(E^{c})= \frac{n(E^{c}) }{n(S)} \\  \\ &#10;P(E^{c})= \frac{3}{12} \\  \\ &#10;P(E^{c})= \frac{1}{4}
7 0
3 years ago
The teacher concluded that there is a correlation between having a computer and having a phone. Do you agree with the teacher? E
timama [110]

Answer:

yes I agree with teacher

Step-by-step explanation:

I I think this because 1 people that have a phone and a computer are the highest group and two becauseit seems that most of the class has a phone it also seems that most of the class has a computer

3 0
3 years ago
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