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Naddik [55]
3 years ago
8

Carl's Comic Books bought a comic book from a wholesaler for $2.50. He marked the book up

Mathematics
1 answer:
Ray Of Light [21]3 years ago
3 0

Answer:

150 should be the answer

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Part A: The area of a square is (9x2 − 12x + 4) square units. Determine the length of each side of the square by factoring the a
Sloan [31]

Answer:

A. (3x-2)^2

B. 5x-4y

5x=4y

Step-by-step explanation:

5 0
3 years ago
Geologist has collected 10 specimens of basaltic rock and 10th specimens of granite. The geologist instructs a laboratory assist
olya-2409 [2.1K]

Answer:

p(5)=0.00136

(a) p(x)=\frac{(10Cx)*((10)C(15-x))}{20C10}

(b)p(10)+p(5)=0.00272

(c)p(7)+p(8)=0.0584

Step-by-step explanation:

If we have N elements with k elements that we consider success and N-k elements that we consider fail, and we take a sample of n elements, the probability that there are x successes in the sample follows a hypergeometric distribution, so it is calculated as:

p(x)=\frac{(kCx)*((N-k)C(n-x))}{NCn}

In this case, N is equal to 20, k is equal to 10 specimens of granite rock, N-k is equal to 10 specimens of basaltic rock and n is 15. So, the probability that there are x specimens of granite rock in the sample or the pmf of the number of granite specimens selected for analysis is:

p(x)=\frac{(10Cx)*((10)C(15-x))}{20C10}

Now, the probability of getting exactly 5 granite specimens selected for analysis is:

p(5)=\frac{(10C5)*((10)C(15-5))}{20C10}=0.00136

On the other hand, the probability that all specimens of one of the two types of rock are selected  for analysis is the probability to select 10 granite specimens or 10 basaltic specimens. Where the probability to take 10 basaltic specimens is equal to the probability to take 5 granite specimens.

Then, the probability that all specimens of one of the two types of rock are selected  for analysis is:

p(10)+p(5)=\frac{(10C10)*((10)C(15-10))}{20C10}+\frac{(10C5)*((10)C(15-5))}{20C10}\\p(10)+p(5)=0.00136+0.00136=0.00272

For the hypergeometric distribution, the mean E(x) and standard deviation S(x) are:

E(x)=\frac{nk}{N}=\frac{15*10}{20}=7.5\\S(x)=\sqrt{\frac{nk}{N}*(1-\frac{k}{N})*(\frac{N-n}{N-1})}\\S(x)=\sqrt{\frac{15*10}{20}*(1-\frac{10}{20})*(\frac{20-15}{20-1})}=0.9934

Then, the number of granite specimens within 1 standard deviation of its mean value is:

  E(x) - S(x) ≤ mean ≤ E(x) + S(x)

7.5-0.9934 ≤ mean ≤ 7.5+0.9934

     6.5066 ≤ mean ≤ 8.4934

               7 ≤ mean ≤ 8

Finally, the probability that the number of granite specimens selected for analysis is  within 1 standard deviation of its mean value is:

p(7)+p(8)=\frac{(10C7)*((10)C(15-7))}{20C10}+\frac{(10C8)*((10)C(15-8))}{20C10}\\p(10)+p(5)=0.0292+0.0292=0.0584

8 0
4 years ago
I need help with these problems 16 20
saul85 [17]
False,31+29=60
true,40+8=48
False,17-7=10
True,98-11=87
False,51-8=43
7 0
4 years ago
Cristina foi a uma livraria para comprar 5 cadernos e 1 livro. O total da conta foi R$ 22,00. Como
Charra [1.4K]

Answer:

eleeeeeeeeee pagoooooooou 3

7 0
3 years ago
Compute 5/3 divided by (-1/2 times -4)
romanna [79]

Answer:

13.3

Step-by-step explanation:

3 0
3 years ago
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