Question

(2x)(x2) + (2x)(x) + (2x)(–2) + (3)(x2) + (3)(x) + (3)(–2) Can someone simplify this

Answer 1

Answer:

$2x^3 + 5x^2 - x - 6$

Step-by-step explanation:

[NOTE]

I am assuming x2 is $x^2$, if I am wrong about that then please notify me in the comments

[END NOTE]

The parenthesis are implications that we multiply the numbers within them.

Therefore, multiply.

(2x)(x2)

$2x^3$

(2x)(x)

$2x^2$

$2x^3 + 2x^2$

(2x)(-2)

-4x

$2x^3+2x^2-4x$

(3)(x2)

$3x^2$

$2x^3+2x^2-4x+3x^2$

(3)(x)

3x

$2x^3+2x^2-4x+3x^2+3x$

(3)(-2)

-6

$2x^3+2x^2-4x+3x^2+3x-6$

Now combine like terms, meaning the numbers with the same endings, you cannot add a number with different exponents and adding numbers with and without a variable.

$2x^3 + 5x^2 - x - 6$