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melamori03 [73]
3 years ago
6

Select the correct answer from each drop-down menu.

Computers and Technology
1 answer:
mylen [45]3 years ago
7 0

Answer:

"In a VPN, a computer connects to a server and then changes the Internet Protocol of your computer" -urgurlmarie

Source: brainly.com/question/19665457, -urgurlmarie

Opinion: You're answer is correct, I'll take this step by step but by connecting your PC to an server like OpenVPN, or a paid VPN service such as Nord VPN. You are changing your Internet Protocol of your PC to that servers I.P. Address.

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In a nested repetition structure, one loop, referred to as the ____ loop, is placed entirely within another loop, called the ___
Alja [10]

Answer:

Inner, outer

Explanation:

Bruh. Its logic

3 0
3 years ago
Write a program that accepts a file name from the command line, then initializes an array with test data using that text file as
postnew [5]

Answer:

Complete code is given below:

Explanation:

import java.io.BufferedReader;

import java.io.FileNotFoundException;

import java.io.FileReader;

import java.io.IOException;

import java.util.Arrays;

import java.util.Scanner;

public class ArrayCalcs {

private int size;

String [] parts =null;

// based on number of elements in file, array will create.

double[] arr=null;

public void readFile(String file){

try{

FileReader fr = new FileReader(file+".txt");

BufferedReader br = new BufferedReader(fr);

String line = br.readLine();

int count = 0;

while (line != null) {

parts = line.split(" ");

for( String w : parts)

{

count++;

}

line = br.readLine();

}

size=count;

arr=new double[size];

for(int i=0;i<size;i++){

arr[i]=Double.parseDouble(parts[i]);

}

// System.out.println(count);

// System.out.println(Arrays.toString(parts));

System.out.println(Arrays.toString(arr));

} catch (FileNotFoundException ex){

System.out.println("This file does not exist");

} catch (IndexOutOfBoundsException e){

System.out.println("Thie file has more than 7 lines");}

catch (IOException e) {

System.out.println(e.getMessage());

}

}

public double getTotal(){

double sum=0.0;

for(double d:arr){

sum=sum+d;

}

return sum;

}

public double getAverage(){

double avg=getTotal()/arr.length;

return avg;

}

public double getHighest(){

double high=arr[0];

for(int i=0;i<arr.length-1;i++){

if(arr[i] > high)

high = arr[i];

}

return high;

}

public double getLowest(){

double low=arr[0];

for(int i=0;i<arr.length-1;i++){

if(arr[i] < low)

low= arr[i];

}

return low;

}

public static void main(String[] args) {

Scanner s = new Scanner(System.in);

System.out.println("Enter file name:");

String file=s.next();

ArrayCalcs ac=new ArrayCalcs();

ac.readFile(file);

System.out.println(" Highest Element: "+ac.getHighest());

System.out.println("Lowest Element: "+ac.getLowest());

System.out.println("Total: "+ac.getTotal());

System.out.println("Average: "+ac.getAverage());

}

}

4 0
3 years ago
Lian is asked to create a variable that will keep track of how many times the user has tried to enter their password. What kind
Kisachek [45]
What are the answers?

Hdhdhdgd. Oxide
4 0
3 years ago
There are two common computer platforms for both PC and MAC users. Which term best describes this function?
andrezito [222]

Operating system (OS)

5 0
3 years ago
What report indicates the last page users viewed before leaving a website?.
Serhud [2]

Answer:

You can find the last page users viewed before leaving the website on the “Exit Pages” report under “Site Content”

Explanation:

This can also give you a percentage of exits as well as the number of exits from a page.

If you have an important page, (using a silly example, a picture of your dog) that you really want people to see, you can check the exit pages and see how many people are actually seeing this <em>great</em> picture of your dog, or adjust your site if needed.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

3 0
2 years ago
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