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3 years ago

Help!!!!!!!!!!!!!!!!!

Computers and Technology

1 answer:

damaskus [11]3 years ago

6 0

The orders are 3465172 hope this helps

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3 years ago

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3 years ago

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3 years ago

Write a program that declares and initializes a variable representing the weight in milligrams from the keyboard. The program di

Burka [1]

Answer:

weight = int(input("Enter weight in milligrams: "))

kilograms = int(weight / 1000000)

grams = int((weight - (kilograms * 1000000)) / 1000)

milligrams = weight - ((kilograms * 1000000) + (grams * 1000))

print("{} milligrams are equivalent to {} kilogram(s), {} gram(s), and {} milligram(s)".format(weight, kilograms, grams, milligrams))

Explanation:

*The code is in Python.

Ask the user to enter the weight and set it to the variable weight

Calculate the kilograms, divide the weight by 1000000 and cast the result to the int (If the weight is 1050042, kilograms would be 1050042/1000000 = 1)

Calculate the grams, subtract the kilograms from the weight, divide it by 1000 and cast the result to the int (If the weight is 1050042, grams would be int((1050042 - (1 * 1000000)) / 1000) = 50)

Calculate the milligrams, subtract the kilograms and grams from the weight (If the weight is 1050042, milligrams would be 1050042 - ((1 * 1000000) + (50 * 1000)) = 42)

Print the weight, kilograms, grams, and milligrams in the required format

3 0

3 years ago

A hardware supplier manufactures three kinds of clamps, types A, B, and C. Production restrictions force it to make 10 more ty

Rufina [12.5K]

Answer:

A = 120

B = 40

C = 70

Solution:

As per the question:

Manufacturer forced to make 10 more type C clamps than the total of A and b:

10 + A + B = C (1)

Also, 3 times as many type B as type A clamps are:

A = 3B (2)

The total no. of clamps produced per day:

A + B + C = 330 (3)

The no. of each type manufactured per day:

Now, from eqn (1), and (3):

A + B + 10 + A + B = 330

2A + 2B = 320

A + B = 160 (4)

Now, from eqn (2) and (4):

3B + B = 160

B = 40

Since, A = 3B

A = $3\times 40$

A = 120

Put the values of A and C in eqn (3):

120 + 40 + C = 330

C = 70

4 0

3 years ago