If C is the midpoint of AB, what is AC:CB

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

5 0

Answer:

AC would be equal to CB, but you didn't give numbers so that's all you can get from what you said

Step-by-step explanation:

You might be interested in

5yr is how many days

Karolina [17]

There are 1,826 days in 5 yr. In relation to the leap year, there are 1826.25 days in 5 yrs. That is because there are really 365.25 days in a year (making every four years a leap year). So, when you multiply 365.25 by 5, you get 1826.25.

6 0

3 years ago

Read 2 more answers

I need help PLEASEEEEEEEEEEEEEE

cupoosta [38]

Answer:

318

Step-by-step explanation:

318 is the required answer

I hope it helped you

So given Figure we need to find total surface area

=Area(ABCD)+Area(BCRQ)+Area(QRSP)+Area(ADSP)+Area(ABQP)+Area(DCRS)

=(AB×BC)+(BC×CR)+(QR×RS)+(AD×DS)+(AB×BQ)+(DC×CR)

From figure,

AB=DC=PQ=SR=9 cm

BQ=CR=AP=DS=11 cm

BC=AD=QR=SP=3 cm

On substituting these values We get

Surface Area=(9×3)+(3×11)+(9×3)+(11×3)+(9×11)+(9×11)

=27+33+27+33+99+99=318

I hope it helped you

4 0

2 years ago

Read 2 more answers

Use the drop-down menus to complete the proof. Given that w ∥ x and y is a transversal, we know that ∠1 ≅∠5 by the . Therefore,

ololo11 [35]

Answer:

From the graph attached, we know that $\angle 1 \cong \angle 5$ by the corresponding angle theorem, this theorem is about all angles that derive form the intersection of one transversal line with a pair of parallels. Specifically, corresponding angles are those which are placed at the same side of the transversal, one interior to parallels, one exterior to parallels, like $\angle 1$ and $\angle 5$ .

We also know that, by definition of linear pair postulate, $\angle 3$ and $\angle 1$ are linear pair. Linear pair postulate is a math concept that defines two angles that are adjacent and for a straight angle, which is equal to 180°.

They are supplementary by the definition of supplementary angles. This definition states that angles which sum 180° are supplementary, and we found that $\angle 3$ and $\angle 1$ together are 180°, because they are on a straight angle. That is, $m \angle 3 + m \angle 1 = 180\°$

If we substitute $\angle 5$ for $\angle 1$ , we have $m \angle 3 + m \angle 5 = 180\°$ , which means that $\angle 3$ and $\angle 5$ are also supplementary by definition.