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Nikolay [14]
3 years ago
7

If the marginal revenue (in dollars per unit) for a month is given by MR = −0.5x + 400, what is the total revenue from the produ

ction and sale of 30 units?
Mathematics
1 answer:
Vesna [10]3 years ago
6 0

Given:

Marginal revenue (in dollars per unit) for a month is

MR=-0.5x+400

To find:

The total revenue from the production and sale of 30 units.

Solution:

We know that, total revenue is integration of marginal revenue with respect to quantity.

TR=\int MR dx

TR=\int (-0.5x+400) dx

TR=-0.5\int x dx+400\int 1 dx

TR=-0.5\times \dfrac{x^2}{2}+400x

Now, substitute x=30 in the equation of Total Revenue (TR).

TR=-0.5\times \dfrac{30^2}{2}+400(30)

TR=-0.5\times \dfrac{900}{2}+12000

TR=-225+12000

TR=11775

Therefore, the total revenue from the production and sale of 30 units is $11,775.

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Answer:

The probability that it came from A, given that is defective is 0.362.

Step-by-step explanation:

Define the events:

A: The element comes from A.

B: The element comes from B.

C: The element comes from C.

D: The elemens is defective.

We are given that P(A) = 0.25, P(B) = 0.35, P(C) = 0.4. Recall that since the element comes from only one of the machines, if an element is defective, it comes either from A, B or C. Using the probability axioms, we can calculate that

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Recall that given events E,F the conditional probability of E given F is defined as

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We are given that given that the element is from A, the probability of being defective is 5%. That is P(D|A) =0.05. Using the previous analysis we get that

P(D) = P(A)P(D|A)+P(B) P(D|B) + P(C)P(D|C) = 0.05\cdot 0.25+0.04\cdot 0.35+0.02\cdot 0.4 = 0.0345

We are told to calculate P(A|D), then using the formulas we have

P(A|D) = \frac{P(A\cap D)}{P(D)}= \frac{P(D|A)P(A)}{P(D)}= \frac{0.05\cdot 0.25}{0.0345}= 0.36231884

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3 years ago
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Nana76 [90]

Answer:

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7 0
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Step-by-step explanation:

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Answer:

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I just started by making an educated guess using the values already given. Then I inserted that into the problem to see if it worked.

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I used 6 as a random, educated guess for the value of w.

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3 years ago
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