Step-by-step explanation:
The area that cow can graze is in the form of semicircle.
Radius of semicircle
Length of rope =14 m
Required area = 1/2 ×πr
=1/2×22/7×r^2
=1/2×22/7×14×14
=308m2
Answer:
THE ANSWER IS THIS FOR THE QUESTION UP TOP
Step-by-step explanation:
1.(4,9) & (1,6)
m=y²-y¹/x²-x¹
m=6-9/1-4
m=-3/-3
m= 1
2.(5,3) & (5,-9)
m=y²-y¹/x²-x¹
m=(-9)-3/5-5
m=-12/0
3.(2,1) & (8,9)
m=y²-y¹/x²-x¹
m=9-1/8-2
m=8/6
m= 4/3
4.(14,-8) & (7,-6)
m=y²-y¹/x²-x¹
m=(-6)-(-8)/7-14
m=2/-7
m= -2/7
5.(4,-3) & (8,-3)
m=y²-y¹/x²-x¹
m=(-3)-(-3)/8-4
m=0/4
m=0
6.(-11,1) & (-2,6)
m=y²-y¹/x²-x¹
m=6-1/(-2)-(-11)
m=5/9
Answer:
it is correct :>
Step-by-step explanation:
<3hope it heps
