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4 years ago

10

Bennett has 3,629.8 square centimeters of material. Which is closest to the radius of the largest sphere he can make using the m

aterial?

1 answer:

Fofino [41]4 years ago

6 0

The answer to your math problem is... the radius of the sphere is 2.499 cm. :)

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Neeeeeeeeeed helpppppppppppppppp

Marina86 [1]

The first option, because if it’s 291 yards and 1/4 BELOW (below: meaning negative because you are under the usual sea level).

-291 (1/4)

Hope this helped!

8 0

3 years ago

A water fountain shoots up a jet of water

notsponge [240]

Could possibly be a geyser

3 0

3 years ago

Solve this problem on paper using all four steps. A girl scout troop sold cookies. If the girls sold 5 more boxes the second wee

zhenek [66]

Assume the girls sold X boxes in the first week. They sold in the second week X+5 and 2X+10 in the third week.

The sum X + X + 5 + 2X + 10 = 431
4X = 416. Therefore X = 104
The answers are:
a0 = 104
a1 = 109
a2 = 218

Hope that helps you :)

6 0

3 years ago

let X represent the amount of time till the next student will arriv ein the library partking lot at the university. If we know t

AlekseyPX

Answer:

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean of 4 minutes

This means that $m = 4, \mu = \frac{1}{4} = 0.25$

Find the probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot:

This is:

$P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2)$

In which

$P(X \leq 132) = 1 - e^{-0.25*132} = 1$

$P(X \leq 2) = 1 - e^{-0.25*2} = 0.393469$

$P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2) = 1 - 0.393469 = 0.606531$

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

4 0

3 years ago

What is 2x+4x7x-19x+7y+9x

s2008m [1.1K]

Answer: do the math, 39x

Step-by-step explanation:2+4=6 times 7=42-19=23+7=30+9=39x

6 0

3 years ago

Read 2 more answers