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3 years ago

Which points are solutions to the linear inequality y < 0.5x + 2? Check all that apply.

Mathematics

2 answers:

hram777 [196]3 years ago

8 0

Answer:

The answers are numbers 1, 3, 5, and 6.

(-3,-2) (–1, –2) (1, –2) (1, 2)

Step-by-step explanation:

marusya05 [52]3 years ago

4 0

Are you given choices?
Plug in the x- and y-coordinates of the given points.
The ones that make the inequality true are solutions.

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What is the surface area of a rectangular prism that has a length of 9 feet, a width of 5 feet, and a height of 7.5 feet?

never [62]

A suitable formula for the surface area of a rectangular prism is ...
A = 2(LW +H*(L +W))
Filling in the given information, we have
A = 2((9 ft)*(5 ft) +(7.5 ft)*(9 ft +5 ft))
A = 2(45 ft² +(7.5 ft)*(14 ft)) = 2(150 ft²)

The surface area of the rectangular prism is 300 ft².

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3 years ago

Write 3.617 correct to 2 decimal places

astra-53 [7]

We don't know what's correct, because we don't know anything about where the number came from. If you want the number ROUNDED to two places, that's 3.62 If you want it TRUNCATED (shortened, trimmed) to two places, that's 3.61 .

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3 years ago

Read 2 more answers

Rectangle RSUT has diagonals that meet at point x.

Stels [109]

Answer:

x=12.5

y=10

Step-by-step explanation:

Properties of rectangle:

Opposite sides are congruent
All angles are right angles
Diagonals bisect each other
Diagonals are of equal length

so from the properties we came to know that diagonals bisects each other and diagonals are of equal length

Given Rectangle RSUT has diagonals that meet at point X.

⇒ $RX=SX=UX=TX=\frac{1}{2}RU=\frac{1}{2}ST$

⇒ $RX=\frac{1}{2}ST$

⇒ $4x=\frac{1}{2}(100)$

⇒ $x=12.5$

Also $XU=RX$

⇒ $(4)(12.5)=5y$

⇒ $5y=50$

⇒ $y=10$

3 0

3 years ago

Find the center and the radius of this equation by completing the

Colt1911 [192]

Answer:

$x^2 +4x +(4/2)^2 +y^2 -20 y +(20/2)^2 +100 = (4/2)^2 +(20/2)^2$

And solving we got:

$x^2 +4x+ 4 +y^2 +20y +100 +100 = 4 +100$

If we subtract 100 from both sides we got:

$(x+2)^2 +(y+10)^2 = 4$

$C= (-2,-10)$

$r = \sqrt{4}=2$

Step-by-step explanation:

For this case we have the following equation given:

$x^2 +4x +y^2 -20 y +100=0$

We want to find a general expression given by:

$(x-h)^2 +(y-k)^2 = r^2$

Where the center is (h.k) and the radius is r.

We can begin completing the squares of the equation given and we got:

$x^2 +4x +(4/2)^2 +y^2 -20 y +(20/2)^2 +100 = (4/2)^2 +(20/2)^2$

And solving we got:

$x^2 +4x+ 4 +y^2 +20y +100 +100 = 4 +100$

If we subtract 100 from both sides we got:

$(x+2)^2 +(y+10)^2 = 4$

Then we can conclude that the center is:

$C= (-2,-10)$

And the radius would be:

$r = \sqrt{4}=2$

6 0

3 years ago

What is the mean of 987,982

hram777 [196]

The mean is the average of the two numbers. It can be calculated by adding the two numbers then dividing the answer by 2.

Therefore:
mean = (987+982) / 2 = 984.5

3 0

3 years ago