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kolbaska11 [484]
3 years ago
12

Solve for the variable -14 = x -7 -12x = 60 x+11 = -11 - x/4 = 2

Mathematics
2 answers:
Maurinko [17]3 years ago
6 0
1) x= -7
2) x= -5
3) x=-22
4) x =8
Not sure about the last one tho
I tried to help :)
Eduardwww [97]3 years ago
5 0

Answer:

x = -7

x = -5

x = -22

x = -8

Step-by-step explanation:

-14 = x - 7 (add 7 on both sides)

-7 = x

-12x = 60 (divide by -12 on both sides)

x = -5

x + 11 = -11 (subtract 11 on both sides)

x = -22

-x/4 = 2 (multiply both sides by 4)

-x = 8 (divide by negative)

x = -8

Hope this helps!!

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How many solutions are there to the quadratic formula 10x + y = -x2 + 2
ELEN [110]
Using quadratic formula you can have a maximum of two solutions. When you set this problem equal to zero, your a=-1, b=-10, c=2
4 0
3 years ago
On a map,1 in. represents 12 mi. Two cities are 6 1/2 in. on a map. How far apart are the actual cities? A. 78 mi B. 72 1/2 mi C
Dovator [93]
1 inch= 12 miles


Multiply 6 1/2 inches by total number of miles per 1 inch (12).

= 6 1/2 * 12
convert to improper fraction

= 13/2 * 12
multiply numerators

= (13*12)/2
multiply in parentheses

= 156/2
divide

= 78 miles


ANSWER: (A) 78 miles

Hope this helps! :)
3 0
3 years ago
If one-sixth of a number plus one-third returns two-thirds of that number What is the number
Solnce55 [7]

Answer:

x= \frac{2}{3}

Step-by-step explanation:

Let the number be x

Given

\frac{1}{6}x + \frac{1}{3} = \frac{2}{3}x

Required

Find x

\frac{1}{6}x + \frac{1}{3} = \frac{2}{3}x

Collect Like Terms

\frac{1}{6}x -  \frac{2}{3}x = - \frac{1}{3}

Take LCM

\frac{1 - 4}{6}x = \frac{-1}{3}

\frac{- 3}{6}x = \frac{-1}{3}

Multiply both sides by 6

6 * \frac{- 3}{6}x = \frac{-1}{3} * 6

-3x= -2

Divide both sides by -3

\frac{-3x}{-3}= \frac{-2}{-3}

x= \frac{2}{3}

Hence, the number is \frac{2}{3}

7 0
3 years ago
F(x)=5x+6 what is the domain and range
kozerog [31]
\mathrm{Domain\:of\:}\:5x+6\:  

\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:\ \textless \ x\ \textless \ \infty \\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix} 

\text{The function has no points nor domain constraints. So, the domain is}

\mathrm{Solution:}\:&\:-\infty \:\ \textless \ x\ \textless \ \infty \\ \: 

\mathrm{Range\:of\:}5x+6  

\begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:\ \textless \ f\left(x\right)\ \textless \ \infty \\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix} 

\mathrm{The\:set\:of\:values\:of\:the\:dependent\:variable = meaning} 

\mathrm{The\:range\:of\:polynomials\:with\:odd\:degree\:is\:all\:the\:real\:numbers} 

\mathrm{Solution:}\:&\:-\infty \:\ \textless \ f\left(x\right)\ \textless \ \infty
4 0
3 years ago
56 students signed up for the school play. About 34% of these students were boys. At the auditions only 31 girls attended. What
Elza [17]

56 students represents 100 % and

X boys represent 34%,

so x= 56•34/100= 19.04 so approximately 19 boys

56-19= 37 girls signed up.

Now 37 girls represent 100% and 31 girls represent x % ,

So x= 31•100/37= 83.78% about 84% of the girls attended

3 0
3 years ago
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