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natima [27]
3 years ago
12

According to​ Charles's law, if the pressure is held​ constant, the volume of a gas varies directly with the temperature measure

d on the Kelvin scale. If the volume of a gas is 192 cubic centimeters when the temperature is 112 ​K, find the volume when the temperature is 147 K.
Mathematics
1 answer:
Ksju [112]3 years ago
7 0

Answer:

V₂ = 252 cm³

Step-by-step explanation:

Charles's law = If the pressure is held​ constant, the volume of a gas varies directly with the temperature measured on the Kelvin scale.

Mathematically, V=kT

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

We have, V₁ = 192 cm³, T₁ = 112 K, T₂ = 147 cm³, V₂ = ?

Using the above relation of Charles's law :

V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{192\times 147}{112}\\\\V_2=252\ cm^3

So, the new temperature is 252 cm³.

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Ken has a pole that is 26 inches long. He wishes to cut it into two pieces so that one piece will be 8 inches longer than the ot
Yuliya22 [10]

Answer:

9 inches

Step-by-step explanation:

Do the question algebraically, represented by this equation:

let x be the shorter piece

x + (x + 8) = 26                      (longer piece is 8 units longer)

Remove brackets

x + x + 8 = 26                 Combine like terms              

2x + 8 = 26                   Start isolating "x"

2x + 8 - 8 = 26 - 8           Subtract 8 from both sides

2x = 18

2x/2 = 18/2           Divide both sides by 2

x = 9                    shorter piece

The shorter piece would be 9 inches.

If you needed the longer piece too:

longer piece = x + 8

x + 8

= 9 + 8

= 17

The longer piece would be 17 inches.

Check your answer:

Longer + Shorter = 26           Substitute the lengths

17 + 9 = 26                    Add

26 = 26                same number

LS = RS                left side equals right side

The answer is correct.

3 0
3 years ago
Suppose that 12% of test scores for the unit 1 test were above 85 and 8% were below 70. Assuming a normal
Doss [256]

Answer:

Mean = 78.2

Standard deviation = 5.8

Step-by-step explanation:

Mathematically z-score;

= (x-mean)/SD

From the question;

12% of test scores were above 85

Thus;

P( x > 85) = 12%

P(x > 85) = 0.12

Now let’s get the z-score that has a probability of 0.12

This can be obtained from the standard normal distribution table and it is = 1.175

Thus;

1.175 = (85 - mean)/SD

let’s call the mean a and the SD b

1.175 = (85-a)/b

1.175b = 85 - a

a = 85 - 1.175b ••••••••(i)

Secondly 8% of scores were below 70

Let’s find the z-score corresponding to this proportion;

We use the standard normal distribution table as usual;

P( x < 70) = 0.08

z-score = -1.405

Thus;

-1.405 =( 70-a)/b

-1.405b = 70-a

a = 70 + 1.405b ••••••(ii)

Equate the two a

70 + 1.405b = 85 - 1.175b

85 -70 = 1.405b + 1.175b

15 = 2.58b

b = 15/2.58

b = 5.81

a = 70 + 1.405b

a = 70 + 1.405(5.81)

a = 78.16

So mean = 78.2 and Standard deviation is 5.8

4 0
3 years ago
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