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natima [27]
2 years ago
12

According to​ Charles's law, if the pressure is held​ constant, the volume of a gas varies directly with the temperature measure

d on the Kelvin scale. If the volume of a gas is 192 cubic centimeters when the temperature is 112 ​K, find the volume when the temperature is 147 K.
Mathematics
1 answer:
Ksju [112]2 years ago
7 0

Answer:

V₂ = 252 cm³

Step-by-step explanation:

Charles's law = If the pressure is held​ constant, the volume of a gas varies directly with the temperature measured on the Kelvin scale.

Mathematically, V=kT

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

We have, V₁ = 192 cm³, T₁ = 112 K, T₂ = 147 cm³, V₂ = ?

Using the above relation of Charles's law :

V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{192\times 147}{112}\\\\V_2=252\ cm^3

So, the new temperature is 252 cm³.

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A team of bakers can roll and form 5 dozen pretzels in 9 minutes. How many pretzels can this team form in 1 hour?
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Reduce to simplest form<br> 3/2 + ( -6/5 ) = ?
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Pleaseee help im really confused
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Which is the approximate solution to the system y = 0.5x + 3.5 and y = − 2/3 x + 1/3 shown on the graph? (–2.7, 2.1) (–2.1, 2.7)
AlekseyPX

Answer:

The approximate solution to the system is (-2.7, 2.1).

Step-by-step explanation:

To solve the system of equations \begin{bmatrix}y=0.5x+3.5\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix} you must:

\mathrm{Rationalize\:equations}\\\\\begin{bmatrix}y=\left(\frac{1}{2}\right)x+\left(\frac{7}{2}\right)\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix}

\mathrm{Subsititute\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\begin{bmatrix}-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\end{bmatrix}

\mathrm{Isolate}\:x\:\mathrm{for}\:-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\\\\-\frac{2}{3}x=\frac{19}{6}+\frac{1}{2}x\\\\-\frac{7}{6}x=\frac{19}{6}\\\\6\left(-\frac{7}{6}x\right)=\frac{19\cdot \:6}{6}\\\\-7x=19\\\\x=-\frac{19}{7}\approx-2.7

\mathrm{For\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\mathrm{Subsititute\:}x=-\frac{19}{7}\\\\y=-\frac{2}{3}\left(-\frac{19}{7}\right)+\frac{1}{3}\\\\y=\frac{15}{7}\approx 2.1

The approximate solutions to the system of equations are:

x=-2.7 ,\:y=2.1

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3 years ago
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