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levacccp [35]
2 years ago
15

5x²—3x—2=0 by completing the square method ​

Mathematics
1 answer:
12345 [234]2 years ago
7 0

Answer:

{1, -2/5}

Step-by-step explanation:

5x^2 - 3x -2 = 0

x^2 - (3/5)x - 2/5 = 0

( x - (3/10) )^2 - (3/10)^2 - 2/5 = 0

( x - (3/10) )^2 = 2/5+9/100

( x - (3/10) )^2 = (7/10)^2

Take square roots on both sides

x - 3/10 = +/- 7/10

x = 3/10 +/- 7/10

= { 1, -2/5 }

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-7x+3y+3

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(4-5+4)=3

(-2x-5x)=-7x

(-4y+7y)=3y

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3 years ago
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3 0
3 years ago
Total profit P is the difference between total revenue R and total cost C. Given the following​ total-revenue and​ total-cost fu
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Answer:

The profit function is:

P(x)=-x^2+1280x-3300

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Step-by-step explanation:

The revenue function is:

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And the cost function is:

C(x)=3300+20x

Then the total profit function will be:

P(x)=R(x)-C(x)=(1300x-x^2)-(3300+20x)=-x^2+1280x-3300

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Therefore, the maximum value of the total profit will occur at its vertex point.

The vertex of a quadratic is given by:

\displaystyle \Big(-\frac{b}{2a}, f\Big(-\frac{b}{2a}\Big)\Big)

In this case, a = -1, b = 1280, and c = -3300.

Then the point at which the maximum profit occurs is at:

\displaystyle x=-\frac{1280}{2(-1)}=640

And the maximum profit will be:

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Answer:

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