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Neko [114]
3 years ago
7

determine the density in kg/m3 of a solid whose mass is 40 and whose dimension in centimetre are 30×4×3​

Physics
1 answer:
Savatey [412]3 years ago
5 0

Answer:

Density = 11.11 kg/m³

Explanation:

Given the following data;

Mass = 40 kg

Dimensions = 30×4×3 = 360 cm³ to m³ = 360/100 = 3.6 m³

Thus, volume = 3.6 m³

Now, we can find the density;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the equation;

Density = \frac{mass}{volume}

Substituting into the equation, we have;

Density = 40/3.6

Density = 11.11 kg/m³

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2 diferencias y 2 similitudes entre la actividad física y el ejercicio físico.
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An astronaut carrying a camera in space finds herselfdrifting away from a space shuttle after her tetherbecomes unfastened. If s
Dahasolnce [82]

Answer:

Explanation:

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3 years ago
Monochromatic light falls on a metal surface that has a work function of 6.7 x 10-19 J. Each photon has an energy of 8.0 x 10-19
alina1380 [7]

Answer:

Correct answer: (a) Ekmax =  1.3 · 10⁻¹⁹ J, (b) ε = 5 eV, (c) f = 1.21 · 10¹⁵ Hz

Explanation:

Given:

photon energy  ε = 8 · 10⁻¹⁹ J

work function for metal  Wf = 6.7 · 10⁻¹⁹ J

(a) Ekmax = ?

The Einstein equation for photo effect is:

ε = Wf + Ekmax  ⇒ Ekmax = ε - Wf

Ekmax = 8 · 10⁻¹⁹ - 6.7 · 10⁻¹⁹ = 1.3 · 10⁻¹⁹ J

Ekmax =  1.3 · 10⁻¹⁹ J

(b)  ε = ? eV

the relationship between 1 eV and 1 J is:

1 eV = 1.6 · 10⁻¹⁹ J

so the energy of one photon in eV equals:

ε = 8 · 10⁻¹⁹ J = 8 · 10⁻¹⁹ / 1.6 · 10⁻¹⁹ eV = 5 eV

ε = 5 eV

(c)  f = ?

the energy of a single photon is calculated according to the formula:

ε = h · f  

where is:

h = 6.62 ·  10⁻³⁴ J s    plank constant

and f  frequency of each photon (electromagnetic radiation)

f = ε / h = 8 · 10⁻¹⁹ J / 6.62 ·  10⁻³⁴ J s = 1.21 · 10¹⁵ s⁻¹ =  1.21 · 10¹⁵ Hz

f = 1.21 · 10¹⁵ Hz

God is with you!!!

8 0
3 years ago
A 1500-kg car traveling at 30 m/s east collides with a 3000-kg car traveling at 20 m/s south. The two cars stick together after
xxMikexx [17]

Answer:

Speed of the cars after the collision is 3.34 m/s.

Explanation:

It is given that,

Mass of one car, m₁ = 1500 kg

Velocity of this car, v₁ = + 30 m/s ( in east )

Mass of other car, m₂ = 3000 kg

Velocity of other car, v₂ = - 20 m/s (in south)

The two cars stick together after the collision. It is a case of inelastic collision. Let v is the speed of cars after collision. It can be calculated using the conservation of linear momentum as :

m_1v_1+m_2v_2=(m_1+m_2)v

v=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}

v=\dfrac{1500\ kg\times 30\ m/s+3000\ kg\times (-20\ m/s)}{1500\ kg+3000\ kg}

v = -3.34 m/s

So, the speed of the cars after the collision is 3.34 m/s. Hence, this is the required solution.

6 0
3 years ago
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