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vesna_86 [32]
3 years ago
13

A skydiver falls out of a plane from rest, and experiences no air resistance. Eventually, this skydiver reaches a velocity of 33

m/s. How much time did this take? *
Physics
1 answer:
shusha [124]3 years ago
3 0

Answer:

the time taken for the motion is 3.37 s

Explanation:

Given;

initial velocity of the skydiver, u = 0

final velocity of the skydiver, v = 33 m/s

The time taken for the motion is calculated as;

v = u + gt

33 = 0 + 9.8t

33 = 9.8t

t = 33 / 9.8

t = 3.37 s

Therefore, the time taken for the motion is 3.37 s

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Answer:

8.1 x 10^13 electrons passed through the accelerator over 1.8 hours.

Explanation:

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Total Charge = - 12960 nC = - 12.96 x 10^(-6) C

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3 years ago
Which of the following is a pair of vector quantities?
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Answer:

velocity and displacement answer

Explanation:

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Consider the image above. Vi = the initial velocity and Vf = the final velocity. Is there acceleration? Explain your answer.
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D) Yes. Even though the initial and final velocities are the same, there is a change in direction for the ball.
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3 years ago
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Is there a picture?
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Several light bulbs, each of resistance 1.5 Ω, are connected in a series across a 120 V source of emf. If the current through th
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<h3><u>Answer;</u></h3>

40 light bulbs

<h3><u>Explanation</u>;</h3>

The total resistance of components or bulbs in series is given as the sum of resistance of all the components.

Thus; if there are bulbs in series each with a resistance of 1.5 Ω, the the total resistance will be; 1.5nΩ

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