What is the upper quartile, Q3, of the following data set? 54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41
scZoUnD [109]
The original data set is
{<span>54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41}
Sort the data values from smallest to largest to get
</span><span>{38, 41, 43, 46, 48, 52, 53, 54, 55, 56, 60, 62, 65, 67, 70}
</span>
Now find the middle most value. This is the value in the 8th slot. The first 7 values are below the median. The 8th value is the median itself. The next 7 values are above the median.
The value in the 8th slot is 54, so this is the median
Divide the sorted data set into two lists. I'll call them L and U
L = {<span>38, 41, 43, 46, 48, 52, 53}
U = {</span><span>55, 56, 60, 62, 65, 67, 70}
they each have 7 items. The list L is the lower half of the sorted data and U is the upper half. The split happens at the original median (54).
Q3 will be equal to the median of the list U
The median of U = </span>{<span>55, 56, 60, 62, 65, 67, 70} is 62 since it's the middle most value.
Therefore, Q3 = 62
Answer: 62</span>
Answer:
12/sin90'=b/sin67'
12sin67'=bsin90'
b=12sin67/sin90'
Step-by-step explanation:
sister ,we can use the law of sines. since we have the angle of elevation and assume the wall makes a right angle with the ground, our angle opposite the ground is 180-[90+23=67
hope this is helpful for you
Answer:
b. A = 71.6°; C = 45.40°; b =15.0
Step-by-step explanation:
The missing values can be found with the help of the Law of Cosine and properties of triangles:
Side b (Law of Cosine)
Angle A (Law of Cosine)
Angle C (Sum of internal angles in triangles)
Hence, the right answer is B.
I can't exactly see if the 10 at the end is negative, but I'm going to assume that it is.
10x - 6y = 8
5x - 10y = -10
= (2, 2)
} I hope this helped! {
Not enough Information. I could say 50 and it would work. I could say 68 and it would work. Any even number thats under 80 but higher than what you think her eldest son is.
