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Lady bird [3.3K]
2 years ago
8

The sides of a right triangle form an arithmetic sequence with the difference d. Find the area of an inscribed circle in terms o

f d.
Mathematics
1 answer:
pantera1 [17]2 years ago
3 0

Answer:

The sides of a right triangle form an arithmetic sequence with the difference is described below in detail.

Step-by-step explanation:

Let's denominate the first term aa and the obvious difference dd. Therefore, your course enhances:

a, a+d, a+2da, a+d, a+2d

Now, these three terms form the sides of a right triangle. Since a+2da+2d is the highest (considering d > 0), we can state that it is the hypothenuse.

applying the Pythagorean Theorem:

a2+(a+d)2=(a+2d)2a2+(a+d)2=(a+2d)2

a2+a2+2ad+d2=a2+4ad+4d2a2+a2+2ad+d2=a2+4ad+4d2

3d2−a2+2ad=03d2−a2+2ad=0

(3d−a)(d+a)=0(3d−a)(d+a)=0

Therefore, your solutions are

3d=a3d=a

andd=−ad=−a

So if a = 3, d = 1. Therfore, one potential  sequence is 3, 4, 5.

Similarly, if a = 6, then d = 2, so another potential sequence is 6, 8, and 10

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Let A = {the Rationals) and B = {the Irrationals). Find AU B.
anzhelika [568]

Answer:

Option B.

Step-by-step explanation:

It is given that

A = {The Rationals}

B = {The Irrationals}

We need to find the set A∪B.

If we have two sets X and Y then union of these sets (X∪Y) contains all the elements of set X, of set Y or both.

It is given that A is the set of rations and B is the set of irrational, so the union A∪B is the combined set of all rational or irrational numbers.

A∪B = {The Rationals} +  {The Irrationals}

A∪B = {The Reals}

Therefore, the correct option is B.

4 0
3 years ago
83/10y-(38/11-11/4y)
IrinaK [193]

Answer:

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Step-by-step explanation:

5 0
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Can someone please be nice enough and give me all the answer for these questions.
PSYCHO15rus [73]
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Answer:

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Step-by-step explanation:

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