Answer:
A man is driving to pick his daughter from school. He waits for his daughter to be done, then he drives back home.
Answer:
0.347% of the total tires will be rejected as underweight.
Step-by-step explanation:
For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.
And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.
1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344
1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792
The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)
Using data from the normal distribution table
P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight
Hope this Helps!!!
Answer:
It is not equivalent.
Step-by-step explanation:
You have to expand the brackets :
(x-4)(x+3)
= x(x) + x(3) - 4(x) - 4(3)
= x² + 3x - 4x - 12
= x² - x - 12
Therefore, x² - x - 12 / (x-4)(x+3) is not equivalent to x² - 4x - 12.
Answer:
180
Step-by-step explanation:
The 12 th square number is
12² = 12 × 12 = 144
The 6 th square number is
6² = 6 × 6 = 36
Thus
sum = 144 + 36 = 180
Answer:
Hello! After reading your question I have deduced that the correct answer is 288² cm.
Step-by-step explanation:
The way I came to this conclusion was as follows:
Firstly:
If said rectangle is two squares put side by side (adjacent), then a valid assumption is that both squares are the same size.
This is because all four sides of a square have to be equal.
Thus if the two squares are joined together on one side, then all the other sides of both the squares will be the same length.
Thus both of the squares are going to be the same size, so they will have the same area.
Secondly:
If the area of one square is 144² cm then the area of the other square should also be 144² cm.
Thus if you combine the areas of both the squares, that make up the rectangle, you are left with the area of the rectangle being 288² cm.
I hope this helped!
