Answer:
Step-by-step explanation:
you first need to change the mixed number to an improper fraction
then multiply the second fraction by 2 so that the denominator is the same in both fractions
Answer:
good
those desert people ought to use less water
The set when z = -5 is {-27, -9, -5}
<h3>How to determine the set elements?</h3>
The set is given as:
{(4z-7,z-4,z) |z is any real number}
When z=-5, we have:
4z - 7 = 4(-5) - 7 = -27
z - 4 = -5 - 4 = -9
z = -5
So, we have:
{(4z-7,z-4,z) |z is any real number} ⇒ {-27, -9, -5}
Hence, the set when z = -5 is {-27, -9, -5}
Read more about sets at:
brainly.com/question/8053622
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Answer:
The solution of the equation 
is 
.
Step-by-step explanation:
Let , we see that number of equation and variables are both the same and can be solved by algebraic means.
1) Given
2) 
Commutative property
3) ![x + [3+(-3)] = 11 + (-3)](https://tex.z-dn.net/?f=x%20%2B%20%5B3%2B%28-3%29%5D%20%3D%2011%20%2B%20%28-3%29)
Compatibility with addition/Associative property
4) Additive inverse/Modulative property/Definition of substraction/Result
The solution of the equation is .
