Answer:
Starting from root, recursively traverse the min-heap. Once we find a key with value less than our X, we know that every key in subtree of that key will be also smaller than our X. Otherwise, we should keep traversing.
Explanation:
The complexity of this algorithm will be O(N) where N is the number of keys in our min-heap.
The term “Renaissance man” means for a very clever person to be good at many different things.
Answer:
1 PROCESSOR :
(1 × 2.56 × 10^9) + (12 × 1.28 × 10^9) + (5 × 2.56 × 10^8) / 2 GHz = 9.6 s
2 PROCESSORS :
(1×2.56×10^9)+(12×1.28×10^9)/0.7×2 + (5 × 2.56 × 10^8) / 2 GHz = 7.04 s
Speed -up is 1.36
4 PROCESSORS :
(1×2.56×10^9)+(12×1.28×10^9)/0.7×4 + (5 × 2.56 × 10^8) / 2 GHz = 3.84 s
Speed -up is 2.5
5 PROCESSORS :
(1×2.56×10^9)+(12×1.28×10^9)/0.7×8 + (5 × 2.56 × 10^8) / 2 GHz = 2.24 s
Speed -up is 4.29
Explanation:
The following formula is used in this answer:
EXECUTION TIME = CLOCK CYCLES / CLOCK RATE
Execution Time is equal to the clock cycle per clock rate
Answer:
see below diagrams.
You could extend that by defining two outputs:
- Lock open/closed indicator
- Error indicator
Then all you have to do is design a circuit...