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liraira [26]
2 years ago
5

19. Determine the midpoint of the line with end points (0,0) and (2,2).​

Mathematics
1 answer:
Anika [276]2 years ago
8 0

Answer:

midpoint m= <u>(</u><u>x1 </u><u>+</u><u>x2</u> , <u>y1 </u><u>+</u><u> </u><u>y2</u><u>)</u>

2. 2

Step-by-step explanation:

M =(<u>0</u><u>+</u><u>2</u><u>. </u>, <u>0</u><u>+</u><u>2</u><u>)</u>

2. 2

M=(1,1)

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1 year ago
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-1.8 - 6x = 6(0.1 + 3x)
Wittaler [7]

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x = -1/10 or -0.1

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telo118 [61]

Answer:

a) 0.033

b) 0.468

c) 100

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 105.3

Standard Deviation, σ = 8

The amount x of miraculin produced (measured in micro-grams per gram of fresh weight) had a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(x > 120)

P( x > 120) = P( z > \displaystyle\frac{120 - 105.3}{8}) = P(z > 1.8375)

= 1 - P(z \leq 1.8375)

Calculation the value from standard normal z table, we have,  

P(x > 120) = 1 - 0.967 = 0.033 = 3.3\%

b) P(x between 100 and 110)

P(100 \leq x \leq 110) = P(\displaystyle\frac{100 - 105.3}{8} \leq z \leq \displaystyle\frac{110-105.3}{8}) = P(-0.6625 \leq z \leq 0.5875)\\\\= P(z \leq 0.5875) - P(z \leq -0.6625)\\= 0.722 - 0.254 = 0.468 = 46.8\%

P(100 \leq x \leq 110) = 46.8\%

c) P(x < a) = 0.25

P( x \leq a) = P( z \leq \displaystyle\frac{a - 105.3}{8}) = 0.25

Calculation the value from standard normal z table, we have,  

P( z \leq -0.674) = 0.25

\displaystyle\frac{x - 105.3}{8} = -0.674\\\\x = -0.674\times 8 + 105.3 = 99.908 \approx 100

3 0
2 years ago
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