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1 year ago

Can you please find the angles with the angles shown? Like the

Mathematics

2 answers:

max2010maxim [7]1 year ago

8 0

Answer:

K=57, G=131, & C= 74

Step-by-step explanation:

K= 7(7)+8

K=57

G= 19(7)-2

G=131

C=10(7)+4

C=74

SashulF [63]1 year ago

4 0

Answer:

Add all of the equations together and make them equal 180. (Solve for X) once you find x plug it back into each equation separately and that will tell you the answer for each angle

Step-by-step explanation:

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Solve for m. –8m = 3 − 9m m =

Oksanka [162]

Answer:

m=3

Step-by-step explanation:

–8m = 3 − 9m

-8+9m = 3

m = 3

8 0

2 years ago

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Can one of you guys help me please :( thank you

timurjin [86]

Answer:

42???

Step-by-step explanation:

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5 0

3 years ago

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1E. The number 2A5A0A2 is divisible by 99. What is the digit A?

kirza4 [7]

Answer: A = 3

Step-by-step explanation:

The digit is 3. If A is 3, the number

2A5A0A2 becomes 2353032. We then divide by 99 and this will be:

= 2353032/99

= 23768

If we use 1, we'll have 2151012. Dividing by 99 gives:

= 2151012 / 99

= 21727.39

If we use 2, we'll have 2252022. Dividing by 99 gives:

= 2252022 / 99

= 22747.69

If we use 4, we will have 2454042. Dividing by 99 gives:

= 2454042 / 99

= 24788.30

If we use 5, we will have 2555052. Dividing by 99 gives:

= 2555052 / 99

= 25808.61

If we use 6, we will have 2656062. Dividing by 99 gives:

= 2656062 / 99

= 26828.91

If we use 7, we will have 2757072. Dividing by 99 gives:

= 2757072 / 99

= 27849.21

If we use 8, we will have 2858082. Dividing by 99 gives:

= 2858082 / 99

= 28869.52

If we use 9, we will have 2959092. Dividing by 99 gives:

= 2959092 / 99

= 29889.82

If we use 0, we will have 2050002. Dividing by 99 gives:

= 2050002 / 99

= 20707.09

Therefore, A is 3 as it gives 2353032 which divides 99 successfully without remainder.

5 0

2 years ago

What values must x have so that log (x) is greater than 2? justify your answer

kotegsom [21]

Answer:

The value of x must be greater than 100.

Step-by-step explanation:

We need to find the value x for which the value of log(x) is greater than than 2.

$log(x)>2$

According to the property of logarithm, if a is a real number.

$log(x)=a \Rightarrow x=10^a$

Using the above property of logarithm, the given inequality can be rewritten as

$x>10^2$

$x>100$

We conclude that the value of log(x) is greater than 2 for real values of x which are greater than 100.

Therefore, the value of x must be greater than 100.

3 0

3 years ago

Eduardwww [97]

Answer:

Just calculate it. It is very easy.

4 0

3 years ago