It will float.. Sorry if i am wrong
Answer:
By Pythagoras,
\displaystyle{r}=\sqrt{{{x}^{2}+{y}^{2}}}r=x2+y2 \displaystyle=\sqrt{{{\left(-{2}\right)}^{2}+{3}^{2}}}=(−2)2+32 \displaystyle=\sqrt{{{4}+{9}}}=\sqrt{{13}}=4+9=13
For this example, we define the trigonometric ratios for θ in the following way:
\displaystyle \sin{\theta}=\frac{y}{{r}}=\frac{3}{\sqrt{{13}}}={0.83205}sinθ=ry=133=0.83205
\displaystyle \cos{\theta}=\frac{x}{{r}}=\frac{{-{2}}}{\sqrt{{13}}}=-{0.55470}cosθ=rx=13−2=−0.55470
\displaystyle \tan{\theta}=\frac{y}{{x}}=\frac{3}{ -{{2}}}=-{1.5}tanθ=xy=−23=−1.5
\displaystyle \csc{\theta}=\frac{r}{{y}}=\frac{\sqrt{{13}}}{{3}}={1.2019}cscθ=yr=313=1.2019
\displaystyle \sec{\theta}=\frac{r}{{x}}=\frac{\sqrt{{13}}}{ -{{2}}}=-{1.80278}secθ=xr=−213=−1.80278
\displaystyle \cot{\theta}=\frac{x}{{y}}=\frac{{-{2}}}{{3}}=-{0.6667}cotθ=yx=3−2=−0.6667
Answer: 160mi
Step-by-step explanation:
To find the area of a rectangle or that kind of shape u need to find the height and width and that would be 8mi and 20mi and of course they're the same on both side so u need to Height x Width so 8x20=160 or 20+20+20+20+20+20+20+20=160 or 8+8+8+8+8+8+8+8+8+8+8+8+8+8+8+8+8+8+8+8=160 but nobody wants to do it that way unless they absolutely have too
Answer: first one
Step-by-step explanation:
