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poizon [28]
3 years ago
12

Brennan studies the relationship shown in the table. Which expression describes a method Brennan could use to determine the y-va

lue when x equals 7?

Mathematics
1 answer:
vlada-n [284]3 years ago
4 0

Answer:

What is the long Division rhyme to help you solve?

What is the long Division rhyme to help you solve?

Step-by-step explanation:

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361m I hope this helps
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3 years ago
How do I find the product when multiplying with decimals<br><img src="https://tex.z-dn.net/?f=0.36%20%5Ctimes%202.4" id="TexForm
stellarik [79]

Step 1:

first let us convert the two decimals into fractions.

0.36=36/100 (since there are two digits after decimal point we divide by 100)

2.4=24/10 (since there are one digit after decimal point we divide by 10)

now we can multiply the fractions

\frac{36}{100}×\frac{24}{10}

multiplying numerator with numerator and denominator with denominator:

\frac{36*24}{100*10}

=\frac{864}{1000}

Now we can convert this back to decimal

864/1000=0.864, moving decimal three digits to the left since we have three zeros in the denominator that is 1000.

Answer=0.864

7 0
3 years ago
The two pentagons shown are similar. What is the value of x?
Shtirlitz [24]

Answer:

c

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
If two of these shapes are randomly chosen, one after the other without replacement, what is the probability that the first will
aleksandrvk [35]

Answer:

P(T\ n\ S) = \frac{1}{14}

Step-by-step explanation:

*Missing Part of the Question*

4 stars

5 triangles

3 circles

3 squares

Required

Determine the probability of triangle being first then square being second

Total = 4 + 5 + 3 + 3

Total = 15

Represent the triangle with T and square with S

So, we're solving for P(T n S)

P(T\ n\ S) = P(T) * P(S)

Solving for P(T)

P(T) = \frac{n(T)}{Total}

P(T) = \frac{5}{15}

Solving for P(S)

The question implies a probability without replacement;

Hence Total has now been reduced by 1

Total = 14

P(S) = \frac{n(S)}{Total}

P(S) = \frac{3}{14}

Recall that

P(T\ n\ S) = P(T) * P(S)

P(T\ n\ S) = \frac{5}{15} * \frac{3}{14}

P(T\ n\ S) = \frac{15}{15 * 14}

P(T\ n\ S) = \frac{1}{14}

Hence, the required probability is

P(T\ n\ S) = \frac{1}{14}

3 0
3 years ago
A photo of a beetle in a science book is increased to 535​% as large as the actual size. If the beetle is 14 ​millimeters, what
AnnZ [28]

Answer: 74.9 millimeters

Step-by-step explanation:

From the question, a photo of a beetle in a science book was.increased to 535​% as large as its actual size and the beetle.has a actual size of 14 ​millimeters,

The size of the beetle on the photo will be 535% of 14 millimeters. This will be:

= 535% of 14

= 535/100 × 14

= 5.35 × 14

= 74.9 millimeters

4 0
3 years ago
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