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2 years ago

Help Asap plz!!!! Thx Give 20 points

Mathematics

1 answer:

Arisa [49]2 years ago

4 0

Answer:

(1,2) is a solution to both equations

Step-by-step explanation:

To determine if (1,2) is a solution to both equations, substitute into the equation and see if it is true

2x+y =4

2(1) + 2 =4

2+2 =4

4=4

true

y =3x-1

2 = 3(1) -1

2 =3-1

2=2

true

Since both statements are true

(1,2) is a solution to both equations

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Find the zeros of polynomial function and solve polynomials equations. f(x)=x^2-x-90

victus00 [196]

The zeros are:

10 and -9

(ten and negative-nine)

6 0

3 years ago

Hem dibuixat tres rectangles. En el primer, la llargada mesura 3 cm més que l'amplada. El segon i tercer rectangle tenen unes di

quester [9]

Resposta:

Primer rectangle:

Amplada = 11

Longitud = 14

Segon rectangle:

Amplada = 12

Longitud = 15

Tercer rectangle:

Amplada = 13

Longitud = 16

Explicació pas a pas:

Donat que:

Primer rectangle:

Amplada = x

Longitud = x + 3

2n rectangle:

Augment de la dimensió d'1 cm respecte al primer rectangle;

Amplada = x + 1

Longitud = x + 4

3r rectangle:

Augment de la dimensió de 2 cm respecte al primer rectangle;

Amplada = x + 2

Longitud = x + 5

Suma dels tres perímetres del rectangle:

Perímetre d'un rectangle: 2 (l + O)

Primer rectangle:

2 (x + x + 3) = 2 (2x + 3) = 4x + 6

2n:

2 (x + 1 + x + 4) = 2 (2x + 5) = 4x + 10

3r:

2 (x + 2 + x + 5) = 2 (2x + 7) = 4x + 14

Suma de perímetres = 162

(4x + 6 + 4x + 10 + 4x + 14) = 162

12x + 30 = 162

12x = 162 - 30

12x = 130

x = 11

Per tant,

Primer rectangle:

Amplada = 11

Longitud = 11 + 3 = 14

2n rectangle:

Amplada = 11 + 1 = 12

Longitud = 11 + 4 = 15

3r rectangle:

Amplada = 11 + 2 = 13

Longitud = 11 + 5 = 16

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Answer:

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