The graph of y=-3x+4 is
1 answer:
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Use Law of Cooling:
T0 = initial temperature, TA = ambient or final temperature
First solve for k using given info, T(3) = 42
Substituting k back into cooling equation gives:
At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
Solve for x:
Sub back into original cooling equation, x = T(t)
Solve for t:
This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM
T0 = initial temperature, TA = ambient or final temperature
First solve for k using given info, T(3) = 42
Substituting k back into cooling equation gives:
At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
Solve for x:
Sub back into original cooling equation, x = T(t)
Solve for t:
This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM
Answer:
10%
Step-by-step explanation:
Given: CP of lemon is $600.
3/4 of lemon sold at 20% loss
Remaining lemon at 20% gain.
Considering the quantity of lemon remain constant.
Cost price of 3/4 of lemon=
As given, 3/4 of lemon sold at 20% loss.
∴ Selling price of
Selling price=
Hence, selling price of 3/4 lemon is $360.
Now, the cost price of remaining lemon
∴ The cost price of
As given, remaining
∴ Selling price of
Selling price of
Hence, selling price of 1/4 lemon is $180
Loss\profit percent=
∴ Loss\profit percent=
Hence, the loss percentage is 10%
Answer:
Quadratic Equation:
From the standard form of a Quadratic Function, we get:
Discriminant:
From the discriminant, we conclude that the equation will have two real solutions.
State that:
By the way, solving the equation given: