Answer:
H. 2
Step-by-step explanation:
√(1 − cos² x) / sin x + √(1 − sin² x) / cos x
Use Pythagorean identity.
sin² x + cos² x = 1
So:
1 − cos² x = sin² x
and
1 − sin² x = cos² x
Substitute:
√(sin² x) / sin x + √(cos² x) / cos x
sin x / sin x + cos x / cos x
1 + 1
2
<h3>
Answer: 216 square feet</h3>
Work Shown:
Old area = 12*15 = 180 square feet
New area = 18*22 = 396 square feet
Difference = New - Old = 396 - 180 = 216
The patio's area increased by 216 square feet.
Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
Answer:
The depth now is 47 feet below the surface of the lake
Step-by-step explanation:
Step 1: Determine initial depth
Initial depth=surface level-depth below surface
where;
Surface level=0, since its the point of reference
depth below surface=96 feet
replacing;
Initial depth=(0-96)=-96 feet
Step 2: Final depth
Final depth=Initial depth+distance covered
where;
Initial depth=-96 feet
distance covered=+49 feet since the scuba driver moves towards the surface
replacing;
distance covered=-96+49=-47 feet
The depth now is 47 feet below the surface of the lake
