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Crank
3 years ago
6

Solve the equation by graphing. 1/3x+ 5 = -2x - 2Please I need the point where the line goes ​

Mathematics
1 answer:
jenyasd209 [6]3 years ago
3 0

Answer:

Check attachment.

Step-by-step explanation:

I graphed it.

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What is the smallest positive integer N such that the value 70 + 30(N) is not a prime number?
matrenka [14]
It is 1
70+30*1=100, which is not a prime number
4 0
3 years ago
Find the GCF from the two numbers and rewrite the sum using nthe distributive property
Vadim26 [7]

Answer:

The greatest common factor is 6.

Step-by-step explanation:

Greatest common factor is 6. If you use the distributive property then the answer would be 6(4) + 6(6) or 6(4+6). Then you distribute the 6 to each digit and should get 24+36.

6 0
2 years ago
What amount of money do you have if you have 5 pennies, 13 nickels, 14 dimes, 2 quarters, and one 5 dollar bill?
BartSMP [9]

Answer:

$7.60

Step-by-step explanation:

  • Penny = $0.01
  • Nickel = $0.05
  • Dime = $0.10
  • Quarter = $0.25

( 5 × 0.01 ) + ( 13 × 0.05 ) + ( 14 × 0.10 ) + ( 2 × 0.25 ) + 5

                -<em>The 5 at the end represents the </em><u><em>one</em></u><em> five dollar bill.</em>

Simplified: (solve what is in the parenthesis)

0.05 + 0.65 + 1.4 + 0.50 + 5 = $7.60

4 0
3 years ago
How do you write this in standard form 2x+3y=12
Akimi4 [234]
To get y by itself subtract 2x from both sides. The left side becomes 3y=12-2x. Then divide by 3 on both sides to get y by itself. Which you get y=4-(2/3)x

6 0
3 years ago
Simplify this please​
Ugo [173]

Answer:

\frac{12q^{\frac{7}{3}}}{p^{3}}

Step-by-step explanation:

Here are some rules you need to simplify this expression:

Distribute exponents: When you raise an exponent to another exponent, you multiply the exponents together. This includes exponents that are fractions. (a^{x})^{n} = a^{xn}

Negative exponent rule: When an exponent is negative, you can make it positive by making the base a fraction. When the number is apart of a bigger fraction, you can move it to the other side (top/bottom). a^{-x} = \frac{1}{a^{x}}, and to help with this question: \frac{a^{-x}b}{1} = \frac{b}{a^{x}}.

Multiplying exponents with same base: When exponential numbers have the same base, you can combine them by adding their exponents together. (a^{x})(a^{y}) = a^{x+y}

Dividing exponents with same base: When exponential numbers have the same base, you can combine them by subtracting the exponents. \frac{a^{x}}{a^{y}} = a^{x-y}

Fractional exponents as a radical: When a number has an exponent that is a fraction, the numerator can remain the exponent, and the denominator becomes the index (example, index here ∛ is 3). a^{\frac{m}{n}} = \sqrt[n]{a^{m}} = (\sqrt[n]{a})^{m}

\frac{(8p^{-6} q^{3})^{2/3}}{(27p^{3}q)^{-1/3}}        Distribute exponent

=\frac{8^{(2/3)}p^{(-6*2/3)}q^{(3*2/3)}}{27^{(-1/3)}p^{(3*-1/3)}q^{(-1/3)}}        Simplify each exponent by multiplying

=\frac{8^{(2/3)}p^{(-4)}q^{(2)}}{27^{(-1/3)}p^{(-1)}q^{(-1/3)}}        Negative exponent rule

=\frac{8^{(2/3)}q^{(2)}27^{(1/3)}p^{(1)}q^{(1/3)}}{p^{(4)}}        Combine the like terms in the numerator with the base "q"

=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)}q^{(1/3)}}{p^{(4)}}        Rearranged for you to see the like terms

=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)+(1/3)}}{p^{(4)}}        Multiplying exponents with same base

=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(7/3)}}{p^{(4)}}        2 + 1/3 = 7/3

=\frac{\sqrt[3]{8^{2}}\sqrt[3]{27}p\sqrt[3]{q^{7}}}{p^{4}}        Fractional exponents as radical form

=\frac{(\sqrt[3]{64})(3)(p)(q^{\frac{7}{3}})}{p^{4}}        Simplified cubes. Wrote brackets to lessen confusion. Notice the radical of a variable can't be simplified.

=\frac{(4)(3)(p)(q^{\frac{7}{3}})}{p^{4}}        Multiply 4 and 3

=\frac{12pq^{\frac{7}{3}}}{p^{4}}        Dividing exponents with same base

=12p^{(1-4)}q^{\frac{7}{3}}        Subtract the exponent of 'p'

=12p^{(-3)}q^{\frac{7}{3}}        Negative exponent rule

=\frac{12q^{\frac{7}{3}}}{p^{3}}        Final answer

Here is a version in pen if the steps are hard to see.

5 0
3 years ago
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