If a2 -2ab + b2 = 9 and a![\begin{gathered} a^2-2ab+b^2=9 \\ aStep 1 factorize[tex]\begin{gathered} a^2-2ab+b^2=(a-b)^2 \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D9%20%5C%5C%20a%3C%2Fp%3E%3Cp%3E%EF%BB%BFStep%201%20%3C%2Fp%3E%3Cp%3Efactorize%3C%2Fp%3E%5Btex%5D%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D%28a-b%29%5E2%20%5C%5C%20%20%5Cend%7Bgathered%7D)
then
[tex]\begin{gathered} (a-b)^2=9 \\ \sqrt{(a-b)^2}=\sqrt{9} \\ a-b=\pm3 \\ \\ aa-b=-3
Answer:
their marriage and 2 years before
Double of 50 is 100, so 28*100=2800, now half of the answer is 2800/2=1400
Answer: 8 quarters 19 dimes
Step-by-step explanation:
we already know 8+19=27, if 4 quarters equals a dollar then you use 4 quarters each to create 2 dollars.
then, use 10 dimes to create another dollar summing it up to $3. now all we have to do is make 90 cents, and we've already used 18 coins.
if we used another 9 dimes, that would equal 90 cents.
in conclusion, 4+4= 8
8+10= 18
18+9= 27, and having $3.90
Answer: 28
Step-by-step explanation: 2x14=28
7x4=28
Both are factors of 28
