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3 years ago

Solve for a. ab+c=d a = b (c-d) Oa- (d-c) b oa=b+ с

Mathematics

1 answer:

anyanavicka [17]3 years ago

5 0

Answer:

The answer is is the middle answer! a= (d - c)

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Step-by-step explanation:

Hope this is helpful! Good Bless youu..

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Give me 2 exponents that equal to 8 :)

alekssr [168]

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3 years ago

Write a whole number and a fraction greater than one to name the part filled.

san4es73 [151]

Examples of this are:
2 and $\frac{6}{3}$

2 and $\frac{12}{6}$

4 and $\frac{8}{2}$

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3 years ago

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago

50 is 25% of what number

Marat540 [252]

200. 50x4=200 hope that helps

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3 years ago

Read 2 more answers

Can any one please help me in this the teacher did not explain this it have to be in the lowest term also no decimal answer than

Zinaida [17]

Answer:

Step-by-step explanation:

$A . -5+3x =-41\\3x=-41+5\\3x = -36\\\frac{3x}{3} =\frac{-36}{3} \\x = -12\\\\\\\\\\B. 7x-4=-2x+11\\Collect-like-terms\\7x+2x=11+4\\9x=15\\\frac{9x}{9} =\frac{15}{9} \\\\x = \frac{5}{3} \\\\C. \frac{-4x}{5} =8\\Cross-multiply\\-4x=40\\\frac{-4x}{4} =\frac{40}{-4} \\x = -10\\\\D. \frac{x}{3} -\frac{1}{2} =\frac{1}{4} \\\frac{x}{3} =1/4+1/2\\\frac{x}{3} = \frac{3}{4} \\Cross-multiply\\4x =9\\4x/4 =9/4\\x = 9/4\\$

$E . -4(6x+1)+3 =11+2(x+2)\\-24x-4+3=11+2x+4\\Collect-like-terms\\-24x-2x=11+4+4-3\\-26x =16\\\frac{-26x}{-26} =\frac{16}{-26}\\ x = -\frac{8}{13}$

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3 years ago