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Luden [163]
3 years ago
13

Find the equation of the line through the points (-2,1) and (5,-20)

Mathematics
1 answer:
ankoles [38]3 years ago
5 0

Answer:

y = -3x - 5

Step-by-step explanation:

First find the slope:  (-20 - 1) / (5 - (-2))  = -3

Then plug in one set of points into the equation y = mx + b.

1 = -3(-2) + b

1 = 6 + b

b = -5

So you can get the equation:  y = -3x - 5

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Suppose that an insect population’s density, in thousands per acre, during year n, can be modeled by the recursive formula: a1 =
vlabodo [156]

Answer:

The population alternates between increasing and decreasing

Step-by-step explanation:

<u><em>The options of the question are</em></u>

A) The population density decreases each year.

B) The population density increases each year.

C) The population density remains constant.

D) The population alternates between increasing and decreasing

we have

a_n=2.9(a_n_-_1)-0.2(a_n_-_1)^2

a_1=8

Find the value of a_2

For n=2

a_2=2.9(a_1)-0.2(a_1)^2

a_2=2.9(8)-0.2(8)^2=10.4

Find the value of a_3

For n=3

a_3=2.9(a_2)-0.2(a_2)^2

a_3=2.9(10.4)-0.2(10.4)^2=8.528

For n=4

a_4=2.9(a_3)-0.2(a_3)^2

a_4=2.9(8.528)-0.2(8.528)^2=10.1858

For n=5

a_5=2.9(a_4)-0.2(a_4)^2

a_5=2.9(10.1858)-0.2(10.1858)^2=8.7887

therefore

The population alternates between increasing and decreasing

7 0
3 years ago
Read 2 more answers
What is the length of the diagonal?
Anon25 [30]
The answer is 16\sqrt{8} i hope this answer helps you!
4 0
4 years ago
Read 2 more answers
Please help with math problem?
Hoochie [10]

Answer:

KM=41.6

Step-by-step explanation:

\frac{HJ}{IJ} =\frac{KM}{ML} \\\frac{8}{6} =\frac{KM}{31.2} \\

Cross Multiply and Solve for KM.

6*KM=8*31.2\\KM=\frac{8*31.2}{6} \\KM=41.6

5 0
2 years ago
Help me please i cant get it
Leni [432]

Answer:

Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.

The total cost of both games is:

X + Y

We know that both games cost just above AED 80

Then:

X + Y > AED 80

From this, we want to prove that at least one of the games costed more than AED 40.

Now let's play with the possible prices of X, there are two possible cases:

X is larger than AED 40

X is equal to or smaller than AED 40.

If X is more than AED 40, then we have a game that costed more than AED 40.

If X is less than or equal to AED 40, then:

X ≥ AED 40

Now let's take the maximum value of X in this scenario, this is:

X = AED 40

Replacing this in the first inequality, we get:

X + Y > AED 80

Replacing the value of X we get:

AED 40 + Y  > AED 80

Y > AED 80 - AED 40

Y > AED 40

So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.

So we proven that in all the possible cases, at least one of the two games costs more than AED 40.

7 0
3 years ago
I could use a hand here
worty [1.4K]

Answer:

A. 48

B. 24

C. C

Step-by-step explanation:

To divide up whole numbers by fractions, you simply need to just multiply the whole number by the reciprocal of the fraction. in other words, flip the fraction.

Ex.

12 ÷ 1/4

=

12 x 4

Ex. 2

12 ÷ 1/2

=

12 x 2

8 0
3 years ago
Read 2 more answers
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