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ikadub [295]
2 years ago
7

A type TW cable containing two No. 12 copper conductors has a maximum overcurrent protection of

Computers and Technology
2 answers:
yulyashka [42]2 years ago
7 0

Answer:

A. 20 A.

Explanation:

The National Electrical Code (NEC) Table 310-16 states that unless there is another specific provision in this code, the overcurrent protection in relation to the conductor types that has an obelisk( ) mark shall not be greater than 15 amps for No. 14, 20 amps for No. 12, and 30 amps for No. 10 copper; or, in relation to aluminum and copper clad aluminum, it shall not be greater than 15 amps for No. 12 and 25 amps for No. 10 after factors for ambient temperature and number of conductors have been adjusted as necessary.

Therefore, a type TW cable containing two No. 12 copper conductors can not have more than 20 A (i.e. 20 amps) overcurrent protection.    

Arisa [49]2 years ago
3 0
I think it is 25 im not sure though
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A manager would like information on the knowledge base searches conducted by customers and call center agents. Which two metrics
RideAnS [48]

Answer:

Option A and Option D are the correct options.

Explanation:

While any information is provided by the manager to its customers which is based on the knowledge of the search conducted.

So, the following knowledge is about the article of the lowest rating and about the search query that has no output.

  • Option B is not correct for the following scenario because the manager is informing about the searches conducted by customers, not for the data category.
  • Option C is not correct for the following scenario because the articles are not created by them.
3 0
3 years ago
Which renewable resources are available at any time?​
nordsb [41]

Answer:

Explanation:

Renewable energy is fuel that comes from a source that can be replenished in a short amount of time. This includes solar, wind, water, geothermal power and bioenergy. While renewable energy sources may not always be available – for example, if there is no wind to drive wind turbines, or cloudy days that reduce solar energy – they play an important part in reducing the use of non-renewable resources. Furthermore, many of these resources do not emit greenhouse gases directly into the atmosphere.

8 0
3 years ago
Create the following SQL Server queries that access the Northwind database. Place them in a zip file and place the zip file in t
neonofarm [45]

Answer:

1. SELECT e.EmployeeID, e.FirstName, e.LastName, COUNT(*) as OrderByEmployee FROM Employees e

JOIN Orders o

ON e.EmployeeID = o.EmployeeID

WHERE YEAR(o.OrderDate) = '1996'

GROUP BY e.EmployeeID,e.FirstName,e.LastName

ORDER BY OrderByEmployee DESC

2. SELECT o.OrderID,c.CustomerID, o.OrderDate,SUM((od.Quantity)*

od.UnitPrice - od.Discount)) as TotalCost FROM Orders o

JOIN [Order Details] od

ON od.OrderID = o.OrderID

JOIN Customers c

ON o.CustomerID = c.CustomerID

WHERE (MONTH(OrderDate)= 7 OR MONTH(OrderDate) = 8) and

YEAR(OrderDate) = 1996

GROUP BY o.OrderID,c.CustomerID, o.OrderDate

ORDER BY TotalCost DESC

3. SELECT c.CustomerID, c.CompanyName, c.City, COUNT(o.OrderID) as TotalOrder, SUM(od.Quantity* od.UnitPrice) as TotalOrderAmount FROM Customers c

JOIN Orders o

ON o.CustomerID = c.CustomerID

JOIN [Order Details] od

ON od.OrderID = o.OrderID

WHERE c.Country = 'USA'

GROUP BY c.CustomerID, c.CompanyName, c.City

ORDER BY c.City, c.CustomerID

4. SELECT c.CustomerID, c.CompanyName, c.City, COUNT(o.OrderID) as TotalOrder, SUM(od.Quantity* od.UnitPrice) as TotalOrderAmount FROM Customers c

JOIN Orders o

ON o.CustomerID = c.CustomerID

JOIN [Order Details] od

ON od.OrderID = o.OrderID

WHERE c.Country = 'USA'

GROUP BY c.CustomerID, c.CompanyName, c.City

HAVING COUNT(o.OrderID) > 3

ORDER BY c.City, c.CustomerID

5. SELECT p.ProductID, p.ProductName, s.ContactName as SupplierName, MAX(o.OrderDate) as LastOrderDateOfProduct FROM Products p

JOIN Categories c

ON c.CategoryID = p.CategoryID

JOIN Suppliers s

ON s.SupplierID = p.SupplierID

JOIN [Order Details] od

ON od.ProductID = p.ProductID

JOIN Orders o

ON o.OrderID = od.OrderID

where c.CategoryName = 'Grains/Cereals'

GROUP BY p.ProductID, p.ProductName, s.ContactName

ORDER BY SupplierName, p.ProductName

6. SELECT p.ProductID, p.ProductName, Count(DISTINCT c.CustomerID ) as OrderByThisManyDistinctCustomer

FROM Products p

JOIN [Order Details] od

ON od.ProductID = p.ProductID

JOIN Orders o

ON o.OrderID = od.OrderID

JOIN Customers c

ON c.CustomerID = o.CustomerID

where YEAR(o.OrderDate) = 1996

GROUP BY p.ProductID, p.ProductName

Explanation:

The six query statements returns data from the SQL server Northwind database. Note that all the return data are grouped together, this is done with the 'GROUP BY' Sql clause.

8 0
2 years ago
each term to the appropriate definition. DBMS data mining hash file index key field locking protocol relation roll back schema S
ikadub [295]

Answer:

1. DBMS

C. <em>A storage system that provides efficient access to randomly chosen items</em>

G. <em>Performs database operations requested by application software</em>

2. data mining

B. <em>The process of extracting hidden information</em>

3. hash file

A. <em>A. means of locating a particular record within a file</em>

4. index key field

F. <em>An item used to identify records uniquely</em>

5. locking protocol

E. <em>A system to guard against database errors due to performing transactions concurrently</em>

6. relation

D. <em>A structural unit (with rows and columns) in a popular database model</em>

7. roll back schema

I. <em>A "road map" of a particular database's design</em>

J. <em>To "unwind" a transaction</em>

8. SQL

H. <em>A popular language that implements relational database operations.</em>

5 0
3 years ago
In JAVA please:
blagie [28]

Answer:

import java.util.Scanner;

public class ArraysKeyValue {

public static void main (String [] args) {

final int SIZE_LIST = 4;

int[] keysList = new int[SIZE_LIST];

int[] itemsList = new int[SIZE_LIST];

int i;

keysList[0] = 13;

keysList[1] = 47;

keysList[2] = 71;

keysList[3] = 59;

itemsList[0] = 12;

itemsList[1] = 36;

itemsList[2] = 72;

itemsList[3] = 54;  

/* Your solution goes here */

for ( i = 0; i < SIZE_LIST; i++){

 if (keysList[i]>50){

  System.out.println(itemsList[i] + " ");  }  }

System.out.println("");

}

}

Explanation:

I will explain the whole program flow.

  • There are two arrays here
  • keysList and itemsList
  • The first list (keysList) contains the following elements:

13 element at first position of the array (0th index)

47 element at second  position of the array (1st index)

71 element at third position of the array (2nd index)

59 element at fourth position of the array (3rd index)

  • The other list (itemsList) contains the following elements:

12 element at first position of the array (0th index)

36 element at second  position of the array (1st index)

72 element at third position of the array (2nd index)

54 element at fourth position of the array (3rd index)

  • The size of the array elements is fixed which is 4 and is stored in the variable SIZE_LIST.
  • Then the loop starts. The loop contains a variable i which is initialized to 0. First it checks if the value of i is less than the size of the list. It is true as SIZE_LIST=4 and i=0.
  • So the program control enters the body of the loop.
  • In first iteration, IF condition checks if the i-th element of the keysList is greater than 50. As i=0 So the element at 0th index of the keysList is 13 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i increments by 1 so now i becomes 1.
  • In next iteration loop again checks if the value of i is less than the size of the list which is true again so the body of the loop executes.
  • IF condition checks if the i-th element of the keysList is greater than 50. As i=1 So the element at 1st index of the keysList is 47 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i is incremented by 1 so now i becomes 2.
  • In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 2 which is less than SIZE_LIST so the body of the loop executes.
  • IF condition checks if the i-th element of the keysList is greater than 50. As i=2 So the element at 2nd index of the keysList is 71 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 2 so the value at the index 2 of the itemsList is displayed in the output which is 72. Next value of i is incremented by 1 so now i becomes 3.
  • In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 3 which is less than SIZE_LIST so the body of the loop executes.
  • IF condition checks if the i-th element of the keysList is greater than 50. As i=3 So the element at 3rd index of the keysList is 59 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 3 so the value at the index 3 of the itemsList is displayed in the output which is 54. Next value of i is incremented by 1 so now i becomes 4.
  • In next iteration loop again checks if the value of i is less than the size of the list which is now false as i=4 which is equal to the SIZE_LIST= 4. So the loop breaks.
  • So the output of the above program is:

72

54

5 0
3 years ago
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