Answer:
plug-in
Explanation:
A Plug-in is a software that provides additional functionalities to existing programs. The need for them stems from the fact that users might want additional features or functions that were not available in the original program. Digital audio, video, and web browsers use plug-ins to update the already existing programs or to display audio/video through a media file. Plug-ins save the users of the stress of having to wait till a new product with the functionality that they want is produced.
Answer:
The Update statement in the DML is used for changing existing data in a table.
Explanation:
Their are following Sql statement in the DML.
Insert
This SQL statement is used for inserting data into the table.
select
This SQL statement is used for retrieving data from database
update
This SQL statement is used for updating data in a table.
delete
This SQL statement is used for delete data from database .
The "UPDATE" SQL statement in DML is used for Modify the data in the existing table .
Following are the syntax of Update SQL query
Update tablename
set column1=value1,column2=value2............column N=valueN
Where condition;
Example :Suppose we have student table and (rollno,name,age and add) are the field for that table we have to change the address of rollno 105
Then we use update query like that
UPDATE STUDENT
SET add='kalam nagar'
where rollno=105;
Domain Name Servers (DNS) are certainly necessary for easy access of resources across a network. The applicable options of the above are A and B - below are explanations as to why.
A: Computers generally are set to automatically obtain DNS information from the network they are connected to or can be pointed to a specific DNS server. This allows for records of where resources (network attach storage devices, other computers on local network, or even website server details) are located on a “master” kind of list so that the local machine’s host file does not have to be routinely updated to contain new addresses.
B: DNS, as explained partially by the answer to A, maintains a type-able or “human readable” domain name for the actual server’s IP address so we don’t have to memorize or keep a list of IPs for where we want to visit on the web (although, Google’s 8.8.8.8 IP address does make it easy). It shows an association between a name/domain name and an IP address so that we can enter something simple (Google.com) and the computer knows where to go (the server at IP address 8.8.8.8) so it can show you the content you want to see.
C: DNS would only simplify remote access if your were attempting LAN (Local Area Network) remote access of another computer on your network. DNS would not make it easier for remote access of a computer on the internet, as most DNS used in non-commercial settings are created and maintained by third-parties that will not put a specific record for one of your computers in it - not that you would want them to either, since it could lead to an open cyber attack.
D: Network throughput is a fancy phrase for network speed. It could be possible that different DNS servers could process requests faster than others, but it is not likely to increase network speed on the whole as navigating via IP or DNS records will be relatively the same speed.
Answer:
WAN router security standard, Web services standard
Explanation:
Complete statement with blanks filled:
In general, WAN-specific standards identify specific security requirements for WAN devices. For example, the WAN router security standard explains the family of controls needed to secure the connection from the internal network to the WAN router, whereas the Web services standard identifies which controls are vital for use of Web services provided by suppliers and external partnerships.
Answer:
Time taken to travel from one track to the next = 0.08ms
Initial track= 15 0
4 (15-4)*(0.08)= 0.88
40 (40-4)*(0.08)= 2.88
35 (40-35)*(0.08)= 0.4
11 (35-11)*(0.08)= 1.92
14 (14-11)*(0.08)= 0.24
7 (14-7)*(0.08)= 0.56
----------------------------------------------
Total seek time=0.88+2.88+0.4+1.92+0.24+0.56=6.88ms
Explanation:
We caculate the seek time for each request, and then add them together to find the total seek time. The final track number for the current request becomes the current track of next request, and this process is repeated till the last request is processed.
