I don't know if you want the whole x+2 on the bottom or not, but I will put it on the bottom for now.
Replace x with (3+h)

f(3+h)=1/[(3+h)+2]

Now if it's supposed to be JUST x in the denominator...
Replace x with (3+h)

f(3+h)=1/(3+h)+2

Best wishes!

3 0

2 years ago

What is 2r - 6r 8 = 40?

Anit [1.1K]

Well first you have to add common like terms in this case 2r and -6r to get -4r now your equation is -4r+8=40, now subtract 8 from both sides to leave r by itself and get -4r=32, now divide both sides by -4 to get r=-8

Hope this helps

3 0

2 years ago

Read 2 more answers

The average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed. What is

Anna35 [415]

Answer:

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

Step-by-step explanation:

We are given that the average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed.

Firstly, Let X = women's gestation period

The z score probability distribution for is given by;

Z = $\frac{ X - \mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = average gestation period = 270 days

$\sigma$ = standard deviation = 9 days

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is given by = P(261 < X < 279) = P(X < 279) - P(X $\leq$ 261)

P(X < 279) = P( $\frac{ X - \mu}{\sigma}$ < $\frac{279-270}{9}$ ) = P(Z < 1) = 0.84134

P(X $\leq$ 261) = P( $\frac{ X - \mu}{\sigma}$ $\leq$ $\frac{261-270}{9}$ ) = P(Z $\leq$ -1) = 1 - P(Z < 1)

= 1 - 0.84134 = 0.15866

<em>Therefore, P(261 < X < 279) = 0.84134 - 0.15866 = 0.68</em>

Hence, probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

3 0

2 years ago

The product of two decimal is 1.5008 if one of them is 0.56 find the other?​

The product of two decimal is 1.5008 if one of them is 0.56 find the other?