3 years ago

The product P of two consecutive natural numbers, the first of which is N

1 answer:

5 0

If your task here is to write an expression for "<span>The product P of two consecutive natural numbers, the first of which is N,"

then you'd get P = N(N+1). N and N+1 are consecutive natural numbers.</span>

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Divide. Assume that no denominator equals zero.

Diano4ka-milaya [45]

So,

We simply invert and multiply.
$\frac{8d^{3} * 24}{6c * c^{3}d^{4}}$

Re-arrange the numbers so that they are easier to understand.
$\frac{(24)(8)(d^{3})}{(6c)(c^{3})(d^4)}$

Factor.
$\frac{(2^5)}{(c^4)(d)}\ or\ \frac{32}{c^{4}d}$

Cancel out 1's.

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3 years ago

Which of the following best describes the set of all numbers of the form a+bi where a and b are any real numbers and i equals sq

Andrei [34K]

<h3>Answer: B) Complex numbers</h3>

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If b = 0 and 'a' is nonzero, then a+bi = a+0i = a which is strictly a real number

If a = 0 and b is nonzero, then a+bi = 0+bi = bi indicating that the number is now purely imaginary

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3 years ago

Find the product: -4/7 (- 13/2)

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