Question

Area plz answrr me sjsksjvdosnsbdo

Answer 1

Given:

The diagram of a figure with sides 14 ft, 30 ft, 21 ft and 18 ft.

To find:

The area of the figure.

Solution:

From the given figure it is clear that if we cut a corner of a rectangle, then we get the same figure.

The sides of a the rectangle are 30 ft and 21 ft.

The height of the triangular part is (30 ft - 18 ft)  and the base is (21 ft - 14 ft).

So, the height of the triangular part is 12 ft and the base is 7 ft.

The area of the rectangle is:

$A_1=length\times width$

$A_1=30\times 21$

$A_1=630$

The area of the triangular part is:

$A_2=\dfrac{1}{2}\times base \times height$

$A_2=\dfrac{1}{2}\times 12 \times 7$

$A_2=6 \times 7$

$A_2=42$

Now, the area of the given figure is:

$A=A_1-A_2$

$A=630-42$

$A=588$

Therefore, the area of the given figure is 588 sq. ft.