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2 years ago

How is 1/2% express decimal function

Mathematics

1 answer:

Reika [66]2 years ago

7 0

Answer:

Converting a fraction to a decimal is just a division operation. So the fraction 1/2 means 1÷2. ... we find 1÷2=0·5. This fraction was easy - just one digit and we are done.

Step-by-step explanation:

hope yall' understood

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Calvin goes shopping over the weekend and buys a new pair of shoes,a T-Shirt, a pair of sunglasses, and a hat that costs $9. The

Angelina_Jolie [31]

Answer:

I got you :)

Step-by-step explanation:

okay so if the hat is 9$ there is only 56$ left . it says the shoes are twice as much as the shirt , so i just went in and seen how much ill have left if i split it all. So i said 32$ for the shoes , because half of 32$ for shoes would mean 16$ for the shirt which would be 48. Then it says the sunglasses are half as much as the shirt and half of 16 is 8. When we add 32+16+8+9 we get 65$.

4 0

3 years ago

Which of the following expressions is 8x + 16 not equivalent

yKpoI14uk [10]

10x-2x-20+4 is incorrect

5 0

3 years ago

Which expression is equivalent??? help!

dexar [7]

Answer:

The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

Step-by-step explanation:

Given:

$\sqrt[3]{256x^{10}y^{7} }$

Solution:

We will see first what is Cube rooting.

$\sqrt[3]{x^{3}} = x$

Law of Indices

$(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}$

Now, applying above property we get

$\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})$

∴ The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

5 0

2 years ago

CAN SOMEONE PLEASE HELP ME!!!

guajiro [1.7K]

dammn im not sure sorry

7 0

2 years ago

Read 2 more answers

Find the value of x for which the function y = x5-x³ + x² - 1 has a local minimum.

melisa1 [442]

The given function presents a local minimum in the coordinates (0,-1).

<h3>Factoring</h3>

In math, factoring or factorization is used to write an algebraic expression in factors. There are some rules for factorization. One of them is a factor out a common term for example: x²-x= x(x-1), where x is a common term.

For solving this question, the given equation should be rewritten from the factoring.

$x^5-x^3+x^2-1=\left(x+1\right)^2\left(x-1\right)\left(x^2-x+1\right)=0$ . Then, you have 3 equations.

From the Zero Factor Principle, you can write

Equation 1

(x+1)²=0

x+1=0

x= -1

Equation 2

x-1=0

x=1

Equation 3

x²-x+1=0

$x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{\left(-1\right)^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\ \\ x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{3}i}{2\cdot \:1}$

From these points it is possible to plot a graph and you can see that the local minimum presents the coordinates (0,-1).

How is 1/2% express decimal function​

How is 1/2% express decimal function