Let's rewrite the equation with x and y on the left side of the equal sign.
5x-4y=8 --------(1)
3x-3y=3---------(2)
Divide equation (2) by 3,
x - y= 1
now we have,
5x-4y = 8 --------(1)
x - y = 1 ---------(2)
To eliminate x, multiply equation (2) by 5. This makes both the coefficients of x to be 5. Subtract the second equation from the first equation.
5x - 4y = 8
(2) * 5 5x - 5y = 5
(-) (+) (-)
----------------
0x +y =3
Therefore, y=3
Substitute the value of y, in any one of the two equations. Let's substitute y in the second equation.
x-3=1
x=4
x=4 and y=3
I’m pretty sure that it is b
Answer:
A. x^2 + 3x + 2
D. 3x^4 + 4x^3 - 3x^2 - 1
E. 3t^3 + 3t^2 + 2t
Step-by-step explanation:
Standard form is where the equation is set up so that the exponents decrease from left to right, and where you put a number with no variable or exponent last.
71/20 or 3.55 as a decimal
